BesslerWheel.com

It's a bit of a shame this is buried in the "beef" thread... it's really quite generalized now! Anyway... LIB: It only matters when one is doing force and torque balances, in an attempt to figure out what the other forces in the system are... One can only consider "real" forces o...

Note that the Professor says, "there is no force radially outward on the body." Indeed he does. He said otherwise, but then he corrected himself. The difference is subtle. But the weight does cause a force to develop due to the constant rotation. Contrary to what many are taught to believ...

Hey Jim, This is where my problem with "Centripetal Force" (or centrifugal, but most people know better that to use that term any more) begins. As I mentioned previously, centripetal forces do not actually exist, but are a simple way of turning F=mA into F=0 by moving the mA term over to t...

Hey Ralph, (whew- two conversations at once- this is getting complicated! Good thing I have multiple personalities) If droop angle changes yet RPM remains constant then "R" is effected thus "V" must change to maintain given rpm. please do not confuse RPM with velocity, RPM must r...

Hey Jim, Before I get too far into deriving your way and my way and comparing, are TC and TG in your picture "flat" on the drawing page (perpendicular to the rope), or in and out of the page? And you guys seem all right... you can start calling me Kevin. I'll update my profile. It was gett...

Jim- cool picture... maybe tonight I'll work on figuring out how to do that (and bullets and superscripts for that matter!). We do disagree on the equation, and the answer, and I think I know why. From my quick calcs, I get aº = 5.03 degrees when RPM = 200, R = 10, W = whatever you'd like. This eve...

the formula becomes K•W•R•Sin(a)•RPM^2=W•R•Cos(a) Now we're getting somewhere! I haven't checked the units to get K, but I'd bet they are right- they let you use speed in RPM (instead of radians/min), weight in lb (instead of mass in lbm or slugs), etc. But there is something funny with...

Well, thanks everyone for not tearing me a new one :) First, The equation the covers the motion of a spinning weight on a rope with a given down angle Theta is: Theta = atan(g/((omega^2)*r)) where theta is the down angle g is the acceleration due to gravity (Jim- I did consider this constant... inte...

LOL... now I've stepped in it! I did misunderstand the technical issue being squabbled about. And with my graceful entrance here, I've made quite the *ss out of myself. But I'm plenty enough of a man to say when I'm wrong, and this it not likely to be the last time I'll have to say it. So let me sta...

If you need a more detailed explanation in order to understand this then I can provide one. That's a good one Jim. I'm a Mechanical Engineer, a certified Professional Engineer licensed by the state, and I used to teach classes in 3D modeling and kinematic analysis software. When I get some more tim...

OK... This thread has annoyed me enough for me to quit my lurking and actually register just so I could post! Am I the only one that sees the misunderstanding behind Jims technical question to Ralph? The "balance" refers to Ralph spinning a weight horizontally, attached only by a rope. Thi...