Mayday! Mayday!!!
Moderator: scott
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- Devotee
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re: Mayday! Mayday!!!
Good Day to ALL!
I have brought some changes in my gravity wheel design:
1. The main wheel rotates on a STATIONARY axle.
2.The pulleys on rim of main wheel are now crossed geared by belt to the
STAIONARY axle.
3. Now, the pulleys and the main wheel turn in the SAME direction.
4. There are NO levers and weights on the pulleys.
5. The torque providing weights NOW swing on (a) rigid arms on rim of main wheel and (b) on flexible strings/cords on moving points (in black ink) on pulleys.
I may have made errors in my thinking.
Raj
I have brought some changes in my gravity wheel design:
1. The main wheel rotates on a STATIONARY axle.
2.The pulleys on rim of main wheel are now crossed geared by belt to the
STAIONARY axle.
3. Now, the pulleys and the main wheel turn in the SAME direction.
4. There are NO levers and weights on the pulleys.
5. The torque providing weights NOW swing on (a) rigid arms on rim of main wheel and (b) on flexible strings/cords on moving points (in black ink) on pulleys.
I may have made errors in my thinking.
Raj
Keep learning till the end.
re: Mayday! Mayday!!!
It's not easy for me to present my gravity wheel concept fairly in my drawings.
Raj
Raj
Keep learning till the end.
re: Mayday! Mayday!!!
I just caught on to something about my gravity wheel design.
The motion of the pulleys turning around the stationary axle, reminding me of the motion of the earth around its axle, with every points moving nearer and further from the axle and returning/resetting to their starting point every 360 degrees rotation.
I am appreciating this similarity of rotational motion.
Raj
The motion of the pulleys turning around the stationary axle, reminding me of the motion of the earth around its axle, with every points moving nearer and further from the axle and returning/resetting to their starting point every 360 degrees rotation.
I am appreciating this similarity of rotational motion.
Raj
Keep learning till the end.
re: Mayday! Mayday!!!
This is BOUND to be a runner!!!
Can you recognise Bessler's in my EUREKA drawing below???
Raj
Can you recognise Bessler's in my EUREKA drawing below???
Raj
Keep learning till the end.
re: Mayday! Mayday!!!
Now I do :-)
Going to build this one?
Marchello E.
Going to build this one?
Marchello E.
Marchello E.
-- May the force lift you up. In case it doesn't, try something else.---
-- May the force lift you up. In case it doesn't, try something else.---
re: Mayday! Mayday!!!
My last drawing based on Bessler's MT 27, contains errors.
The weights nearest to the 3 o'clock and 9 o'clock positions SHOULD hang/swing perpendicular from their pivot points on the rim of the wheel.
My new drawing below , is based on SWASTIKA concept.
1 is a drum wheel.
2 are special levers made up of three parts, connected diametrically to rim of wheel.
3 are pairs of weights swinging on special levers as in drawing, in separate vertical compartments.
Two special levers at 90 degrees intervals form a swastika.
The wheel in the drawing is in UNSTABLE equilibrium. Any slightest motion clockwise, the weight at the 3 o'clocfk, will come crashing on rim of wheel and the impact must make the wheel rotate a bit.
The wheel MUST rotate a minimum of 22.5 degrees to reach a STABLE equilibrium.
Will the two connected weights impacting at the 3 o'clock position on the rim in the same direction as the wheel is rotating, provide enough IMPULSE and TORQUE to a minumum of 45 degrees turn to reset to the next UNSTABLE equilibrium position of wheel???
That is the QUESTION here!!!
Raj
The weights nearest to the 3 o'clock and 9 o'clock positions SHOULD hang/swing perpendicular from their pivot points on the rim of the wheel.
My new drawing below , is based on SWASTIKA concept.
1 is a drum wheel.
2 are special levers made up of three parts, connected diametrically to rim of wheel.
3 are pairs of weights swinging on special levers as in drawing, in separate vertical compartments.
Two special levers at 90 degrees intervals form a swastika.
The wheel in the drawing is in UNSTABLE equilibrium. Any slightest motion clockwise, the weight at the 3 o'clocfk, will come crashing on rim of wheel and the impact must make the wheel rotate a bit.
The wheel MUST rotate a minimum of 22.5 degrees to reach a STABLE equilibrium.
Will the two connected weights impacting at the 3 o'clock position on the rim in the same direction as the wheel is rotating, provide enough IMPULSE and TORQUE to a minumum of 45 degrees turn to reset to the next UNSTABLE equilibrium position of wheel???
That is the QUESTION here!!!
Raj
Keep learning till the end.
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- Devotee
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re: Mayday! Mayday!!!
Hey Raj,
Recently I was looking at Bessler related images on Google image search, and I remember seeing something almost exactly like that. The connecting rods may be a tad shorter, though.
So, here is a whole thread about that basic design for which jim_mich did quite a few simulations at overunity.com:
http://overunity.com/558/bessler-wheel-design/
Dwayne
ETA: Though I have recently looked at random Bessler related images on Google image search, I now believe I first saw that basic design and its overunity.com thread while looking up a specific individual who happened to have posted in that thread.
He had made a post apparently related to the James Randi Million Dollar Challenge on the International Skeptics Forum (ISF), which used to be the JREF forum, not too long ago and I thought I recognized his screen name from free energy sites and possibly as one of us. That's why I was searching for him.
Actually, I now see that he has posted here but was banned. Anyway, I was just trying to remember how I stumbled upon that thread.
Recently I was looking at Bessler related images on Google image search, and I remember seeing something almost exactly like that. The connecting rods may be a tad shorter, though.
So, here is a whole thread about that basic design for which jim_mich did quite a few simulations at overunity.com:
http://overunity.com/558/bessler-wheel-design/
Dwayne
ETA: Though I have recently looked at random Bessler related images on Google image search, I now believe I first saw that basic design and its overunity.com thread while looking up a specific individual who happened to have posted in that thread.
He had made a post apparently related to the James Randi Million Dollar Challenge on the International Skeptics Forum (ISF), which used to be the JREF forum, not too long ago and I thought I recognized his screen name from free energy sites and possibly as one of us. That's why I was searching for him.
Actually, I now see that he has posted here but was banned. Anyway, I was just trying to remember how I stumbled upon that thread.
I don't believe in conspiracies!
I prefer working alone.
I prefer working alone.
re: Mayday! Mayday!!!
If you rotate your last drawing a few degrees clockwise,it seems as though it will be so bottom heavy at that point that further rotation would be very difficult in either direction.But if you could find a way to pull one of the upper three weights along with the one falling towards the rim,it might give enough overbalance along with the impact to get past the keel position.
Trying to turn the spinning in my brain into something useful before moving on to the next life.
re: Mayday! Mayday!!!
Thank you, Sleepy.
The first drawing below, is showing my last drawing rotated 22.5 degrees clockwise, from the balance UNSTABLE equilibrium position, following the impact by the falling pair of weights.
You will appreciate that the wheel is NOW in balance STABLE equilibrium.
The point to remember here is that the wheel need only a SLIGHT move to topple the UNSTABLE equilibrium and provide rotational torque, and the impact of the falling wait is a BONUS force to make the wheel rotate a few degrees more.
The second drawing shows the position of the wheel some 12 degrees before reaching the resetting point of the next UNSTABLE equilibrium.
The green and blue lines show the horizontal distance of the weights from the central line through the axle. From this one can deduce the clockwise and counter clockwise torque on the wheel.
I just don't know what is the remaining residual impact/implse force left at this point, from the falling weights
Edited 25/09/2015:
You will notice in the second drawing, the weight NOW near the 9 o'clock position, after turning 22.5 degrees plus, is hanging/ swinging almost perpendicular on the rim of the wheel.
In the test video, you will see that when the weight at the 9 o'clock position reaches a perpendicular position, it immediately tilt towards the axle, pushing the weight at the other end to move up and down to hit the rim of the wheel on the descending side, thus providing additional torque for further rotation of wheel.
Dwayne, sorry my friend.
I should thank you, for your batch of eye-opening infos. I did go through the links and I am very happy to see the works of so many friends on a similar approach/concept.
What makes a difference between mine and theirs is that my concept is linked to the SWASTIKA SYMBOL, whereby the changes of positions of the weights happen through the centre of the wheel.
Raj
The first drawing below, is showing my last drawing rotated 22.5 degrees clockwise, from the balance UNSTABLE equilibrium position, following the impact by the falling pair of weights.
You will appreciate that the wheel is NOW in balance STABLE equilibrium.
The point to remember here is that the wheel need only a SLIGHT move to topple the UNSTABLE equilibrium and provide rotational torque, and the impact of the falling wait is a BONUS force to make the wheel rotate a few degrees more.
The second drawing shows the position of the wheel some 12 degrees before reaching the resetting point of the next UNSTABLE equilibrium.
The green and blue lines show the horizontal distance of the weights from the central line through the axle. From this one can deduce the clockwise and counter clockwise torque on the wheel.
I just don't know what is the remaining residual impact/implse force left at this point, from the falling weights
Edited 25/09/2015:
You will notice in the second drawing, the weight NOW near the 9 o'clock position, after turning 22.5 degrees plus, is hanging/ swinging almost perpendicular on the rim of the wheel.
In the test video, you will see that when the weight at the 9 o'clock position reaches a perpendicular position, it immediately tilt towards the axle, pushing the weight at the other end to move up and down to hit the rim of the wheel on the descending side, thus providing additional torque for further rotation of wheel.
Dwayne, sorry my friend.
I should thank you, for your batch of eye-opening infos. I did go through the links and I am very happy to see the works of so many friends on a similar approach/concept.
What makes a difference between mine and theirs is that my concept is linked to the SWASTIKA SYMBOL, whereby the changes of positions of the weights happen through the centre of the wheel.
Raj
Keep learning till the end.
re: Mayday! Mayday!!!
A still picture of the Stable/Unstable Equilibrium initial concept test:
Keep learning till the end.