NEWS FLASH!! Fcdriver has a working wheel!!!!

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Post by WaltzCee »

Mark wrote:Can you provide an estimate as to when the paint will be dry?
Watched paint never dries.

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Post by Grimer »

Fcdriver wrote:
Mark wrote:Mr. Driver

Can you provide an estimate as to when the paint will be dry?

Thanks
Built the stage yesterday, putting plywood on roof today, will be moving the wheel first of the week, by Friday I hope, I'll be ready
It sounds as though you are going to beat our other Trevor (not Lyn Whatford) who posted:
15th May 2013, 5:00 pm : A working wheel is only days away!

In fairness, he never said how many days. :-)
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re: NEWS FLASH!! Fcdriver has a working wheel!!!!

Post by rlortie »

Fcdriver writes:
It is a seven ft diameter wheel, with 4 1/2 ft arm, I did not push the wheel I let go, of a arm, which raised another to its point of drop. I had been using steel cable to keep the wheel from turning, by a loop over a bolt, but it had come loose

How much force does it take to move a weight on a 2 degree incline? If you double or triple that force, for the down stroke, with mechanical advantage.
The amount of force does not interest me as much as distance! what is the lineal distance (in circumference) required to move a weight in 2 degree increments back to its point of working potential leverage? Note: you only have 3.5' radius to accomplish this?
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re: NEWS FLASH!! Fcdriver has a working wheel!!!!

Post by Tarsier79 »

Exactly Ralph. What FC describes are the infant ideas one has when they first start looking into PM. We soon learn these principles do not work.

I don't beleive FC has a working wheel, and I think he is exaggerating/lying when he describes it. I suspect there will be more excuses to come.
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Post by Fcdriver »

So what and how much was the offset? What degree was the incline?
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re: NEWS FLASH!! Fcdriver has a working wheel!!!!

Post by rlortie »

Fcdriver wishes to play games! He wants to see who can come closest to winning the brass ring.

"So what and how much was the offset? What degree was the incline?"

The offset can be anything past the balance point. The incline could be zero
and/or irrelevant.

The driving force in a 180 degree fall is only lifting the same amount if not more weight 2 degrees. Meaning you have 90 drivers to get one weight back to 12:00 for a ratio of 1:90

This of course does not account for the fact that the driving weight lifting its counter part 2 degrees does not pass six and stays there.
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Post by Fcdriver »

The offset gives you mechanical advantage, by pushing down, with leverage, increasing the force, rather than just free falling
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Re: re: NEWS FLASH!! Fcdriver has a working wheel!!!!

Post by Fcdriver »

rlortie wrote:Fcdriver wishes to play games! He wants to see who can come closest to winning the brass ring.

"So what and how much was the offset? What degree was the incline?"

The offset can be anything past the balance point. The incline could be zero
and/or irrelevant.

The driving force in a 180 degree fall is only lifting the same amount if not more weight 2 degrees. Meaning you have 90 drivers to get one weight back to 12:00 for a ratio of 1:90

This of course does not account for the fact that the driving weight lifting its counter part 2 degrees does not pass six and stays there.
Do me a favor take a bathroom scale, attach a 48" arm to a pivot( on the end) put a 10 lb weight on the (other)end, put a 1x2 along the length, (pushing down on to your scale)what does the scale read each time you more the 1x2 along the length ? What is the max force of a 10 lb weight?
Last edited by Fcdriver on Sun Jan 03, 2016 7:10 am, edited 2 times in total.
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re: NEWS FLASH!! Fcdriver has a working wheel!!!!

Post by rlortie »

Fcdriver,

I will play your game only because cold weather keeps me from doing what I should be doing.

"Attach a 48" arm to a pivot". What does the arm consist of and at what point do I place the pivot? "Put a 10 lb weight on the end". Which end if the pivot is not centered, or does it matter as the weight will cause it and the arm to rest on the floor. "Put a 1x2 along the length". Which side of pivot do I place the 1x2, on the side with the weight resting on the floor or the end up in the air? "what does the scale read each time you move the 1x2 along the length? depends on which side of the pivot and weight it is place upon. "What is the max force of a 10 lb weight?" 10 pounds if it is sitting on the floor!

If I move the 1x2 outward from pivot and on the opposite side of the weight the scales will increase by leveraging the 10 pounds resting on the floor, but it must be a very heavy 1x2 to show any significant gain on a 24" pivot providing the pivot is centered.
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Post by rlortie »

Fcdriver wrote:The offset gives you mechanical advantage, by pushing down, with leverage, increasing the force, rather than just free falling
A class one lever, I am sure most here understand that! As a carpenter, with claw-hammer I am assured you are familiar with it!

MA = Input Distance/Output Distance. Mechanical Advantage equal to the Input Distance divided by the Output Distance.
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Post by Fcdriver »

A class one? Or a class two?three?
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Post by Fcdriver »

If the lever pivot is offset, from the center of the wheel( your bathroom scales), how much force can you develop ?
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Post by Fcdriver »

Now put your 90 arms if you wish, how high do you have to lift the weight? Per number of arms?
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Post by Fcdriver »

Try one more thing for me would you, take a pencil hold by the end with it parallel to the floor try to hold a ball against the wall,,now hold the pencil vertical, and try to hold a ball against the wall. This is the difference between, a oscillating cam follower and a translating cam follower.
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Post by Grimer »

Fcdriver wrote:Now put your 90 arms if you wish, how high do you have to lift the weight? Per number of arms?
I love the orthogonality of that last statement, Frank.

Swap the D for a G and the v for an m and you could be me. :-)
Last edited by Grimer on Sun Jan 03, 2016 9:15 am, edited 1 time in total.
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