T-Pendulum under stress
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T-Pendulum under stress
When we construct a T-pendulum as shown in the pictures we can set the T-Pendulum under stress.
The T-Pendulum can move the forces not only up and down, it can also pushback in vertical direction.
So we can use gravity to lift and shift in one go.
We can use the T-Pendulum construction to bring the tumbling oktogon out of balance.
The t-pendulum construction is not driving te wheel directly, there is a construction like the tumbling oktogon between the hamster cage and the t-pendulum.
A system under stress has the possibility to self start.
Stress is produced and gravity can react.
The T-Pendulum can move the forces not only up and down, it can also pushback in vertical direction.
So we can use gravity to lift and shift in one go.
We can use the T-Pendulum construction to bring the tumbling oktogon out of balance.
The t-pendulum construction is not driving te wheel directly, there is a construction like the tumbling oktogon between the hamster cage and the t-pendulum.
A system under stress has the possibility to self start.
Stress is produced and gravity can react.
Best regards
Georg
Georg
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re: T-Pendulum under stress
Here you can see how the T-Pendulum can be used.
The aim of te construction is to bring the oktogon to fall.
With the T-pendulum we can apply an internal force against the oktogon only with the help of gravity.
This construction allowes any force in any direction. I use the construction in that way that the oktogon will fall. The oktogon is like a moveable wall, receding wall.
The oktogon is powering the hamster cage. So the powering of the hamster cage is indirect.
The aim of te construction is to bring the oktogon to fall.
With the T-pendulum we can apply an internal force against the oktogon only with the help of gravity.
This construction allowes any force in any direction. I use the construction in that way that the oktogon will fall. The oktogon is like a moveable wall, receding wall.
The oktogon is powering the hamster cage. So the powering of the hamster cage is indirect.
Best regards
Georg
Georg
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Hey Georg, did some tests on this model. I will try and see if i can do the measurements you sent me.
Here is the video: https://youtu.be/OtunueiWXio
Good Luck!
Here is the video: https://youtu.be/OtunueiWXio
Good Luck!
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re: T-Pendulum under stress
Hi TheVisitorV,
have a look again to the drawing. The force against the octogon must be applied where I had shown the orange arrow.
On the top of the left swingable lever I have a inline scater roller, which will press against the octogon.
In your construction you used the down weight to press against the octogon.
If you don't see it, the octogon is the top heavy weight of the T-Pendulum construction.
So with the t-Pendulum construction we can transfer forces at the highest internal point of the octogon.
The basic of this construction is to make the octogon fall. As higher you can apply a force, as easier it is to bring it to fall.
So again, the octogon is the top heavy weight.
If I find time in the afternoon I will send you an additional drawing for clarification.
have a look again to the drawing. The force against the octogon must be applied where I had shown the orange arrow.
On the top of the left swingable lever I have a inline scater roller, which will press against the octogon.
In your construction you used the down weight to press against the octogon.
If you don't see it, the octogon is the top heavy weight of the T-Pendulum construction.
So with the t-Pendulum construction we can transfer forces at the highest internal point of the octogon.
The basic of this construction is to make the octogon fall. As higher you can apply a force, as easier it is to bring it to fall.
So again, the octogon is the top heavy weight.
If I find time in the afternoon I will send you an additional drawing for clarification.
Best regards
Georg
Georg
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re: T-Pendulum under stress
Here are some more pictures to clarify.
Normally we use an external force to let a body fall.
This, we cannot do in a Besslerwheel. We must have this force covered so that nobody can see it.
The aim is to bring the octogon to fall, but not with an external force, no with an internal. (the internal force is still a external but it is inside).
To manage this we can use a variation of a T-Pendulum.
A normal T-Pendulum has one axis, and therefore we cannot apply a force to the octogon.
The variation has 2 axis, as you can see in the drawings. Now the octogon set the T-pendulum under stress. Putting it under stress will have as a result a lift against gravity.
Now gravity can be used to bring the octogon to fall.
Normally we use an external force to let a body fall.
This, we cannot do in a Besslerwheel. We must have this force covered so that nobody can see it.
The aim is to bring the octogon to fall, but not with an external force, no with an internal. (the internal force is still a external but it is inside).
To manage this we can use a variation of a T-Pendulum.
A normal T-Pendulum has one axis, and therefore we cannot apply a force to the octogon.
The variation has 2 axis, as you can see in the drawings. Now the octogon set the T-pendulum under stress. Putting it under stress will have as a result a lift against gravity.
Now gravity can be used to bring the octogon to fall.
Best regards
Georg
Georg
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re: T-Pendulum under stress
Reminds me of the simple "Grasshopper" clock escapement:
https://www.youtube.com/watch?v=mFbfe0DFu8Q
Unfortunately you still need and outside force to keep running, either springs or weights.
https://www.youtube.com/watch?v=mFbfe0DFu8Q
Unfortunately you still need and outside force to keep running, either springs or weights.
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re: T-Pendulum under stress
Hi Rlortie,
the function is a little bit different.
What I try to do is, to let the octagon fail forward. Tilting.
The octagon will fail in the hamster cage and drive the wheel.
So we get 8 impacts per turn.
The outside force which you mentioned is inside produced. The weights are acting inside of the wheel.
The mechanism is like a overload function, the T-pendulum construction can produce any force to any angle inside of the octagon.
can you open this ?
https://email.t-online.de/em/bin/servic ... Delivery=1
If not I will try to reduce the size.
the function is a little bit different.
What I try to do is, to let the octagon fail forward. Tilting.
The octagon will fail in the hamster cage and drive the wheel.
So we get 8 impacts per turn.
The outside force which you mentioned is inside produced. The weights are acting inside of the wheel.
The mechanism is like a overload function, the T-pendulum construction can produce any force to any angle inside of the octagon.
can you open this ?
https://email.t-online.de/em/bin/servic ... Delivery=1
If not I will try to reduce the size.
Best regards
Georg
Georg
re: T-Pendulum under stress
You need at least two pendulums.
Its the phase difference between two pendulums leading to a
gravity potential vs stress/strain potential which provides a
energy producing cycle, a gravity / stress cycle.
See attachment below.
Its the phase difference between two pendulums leading to a
gravity potential vs stress/strain potential which provides a
energy producing cycle, a gravity / stress cycle.
See attachment below.
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re: T-Pendulum under stress
Hi Vina1,
you are right, we have 2 pendulums which are to close together.
The octagon is a Pendulum when turned in the wheel.
And in addition you have the T-Pendulum under stress.
See that the octagon is an oscillator.
https://www.youtube.com/watch?v=F5aAFY0YByY
With the side+up force of the T-pendulum construction the octagon will always fall in one direction.
you are right, we have 2 pendulums which are to close together.
The octagon is a Pendulum when turned in the wheel.
And in addition you have the T-Pendulum under stress.
See that the octagon is an oscillator.
https://www.youtube.com/watch?v=F5aAFY0YByY
With the side+up force of the T-pendulum construction the octagon will always fall in one direction.
Best regards
Georg
Georg
Re: re: T-Pendulum under stress
I agree. A pendulum is simply a particular case of a gravity field oscillator.Georg Künstler wrote:Hi Vina1,
you are right, we have 2 pendulums which are to close together.
The octagon is a Pendulum when turned in the wheel.
And in addition you have the T-Pendulum under stress.
See that the octagon is an oscillator.
https://www.youtube.com/watch?v=F5aAFY0YByY
With the side+up force of the T-pendulum construction the octagon will always fall in one direction.
We canextend the notion of a pendulum as far as our imagination can take us.
The cycloid pendulum which uses a flexible string rather than a rigid shaft is a good example.
Likewise any stress/strain oscillation is an E.M. oscillation which is an independent field from gravity.
The important thing is to have the fields oscillating out of phase to some extent so as to create an energy enclosing cycle.
I wouldn't like to try delineating such a cycle in the case of your device but the proof of the pudding is in the eating.
If you can get it to overcome losses and generate continuous motion of any kind then there must be an underlying Gravity - E.M. cycle.
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re: T-Pendulum under stress
Hi Vina1,
yes the phase must be shift so that you get an overlay or substraction of the amplitude of the two oscillations.
The T-Pendulum construction is producing a half sinus shape in the upper part of the octagon, the down part of the sinus shape is truncated.
What i have discovered is that the falling octagon must fall ahead by some degrees. German "vorauseilen" engish "Run ahead".
But you are right, we can make several eaysier constructions than the T-Pendulum. I posted it only that you can see how to create the stress in the wheel only with gravity force.
If I find some time in the evening i will post an other possibility with springs.
this will show it more clearly. We deal here with a top Heavy Pendulum.
yes the phase must be shift so that you get an overlay or substraction of the amplitude of the two oscillations.
The T-Pendulum construction is producing a half sinus shape in the upper part of the octagon, the down part of the sinus shape is truncated.
What i have discovered is that the falling octagon must fall ahead by some degrees. German "vorauseilen" engish "Run ahead".
But you are right, we can make several eaysier constructions than the T-Pendulum. I posted it only that you can see how to create the stress in the wheel only with gravity force.
If I find some time in the evening i will post an other possibility with springs.
this will show it more clearly. We deal here with a top Heavy Pendulum.
Best regards
Georg
Georg
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re: T-Pendulum under stress
Octagon with springs:
The octagon can freely fall forward in the hamster cage.
The rollable cylindrical weights are connected with springs and are in contact on the upper area of the octagon wheel.
The weight of the octagon wheel will compress the upper spring.
When the wheel is turned out of position,
the octagon will fall and the spring will release its energy which was primarly stored from the weight of the octagon.
The springs are connected at the same axle as the axle of the hamster cage with a hollow shaft.
Because the octagon is smaller in diameter as the hamster cage we have like a shift of the axle upwards.
This will cause a pressure on the upper spring.
The center point of the octagon is not identical with the center point of the hamster cage.
Only one spring is under stress every time.
The falling octogon will drive the hamster cage.
The octagon can freely fall forward in the hamster cage.
The rollable cylindrical weights are connected with springs and are in contact on the upper area of the octagon wheel.
The weight of the octagon wheel will compress the upper spring.
When the wheel is turned out of position,
the octagon will fall and the spring will release its energy which was primarly stored from the weight of the octagon.
The springs are connected at the same axle as the axle of the hamster cage with a hollow shaft.
Because the octagon is smaller in diameter as the hamster cage we have like a shift of the axle upwards.
This will cause a pressure on the upper spring.
The center point of the octagon is not identical with the center point of the hamster cage.
Only one spring is under stress every time.
The falling octogon will drive the hamster cage.
Best regards
Georg
Georg
re: T-Pendulum under stress
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http://www.youtube.com/c/JulioAntonioCortezRuizVelasco
Here are some ideas of perpetual motion
http://www.youtube.com/c/JulioAntonioCortezRuizVelasco