A simple electric heater, which has efficiency greater than 1

[Georg Künstler]

Hi George1,

i suggest to use Meyers patent to seperate water in Oxygen and hydrogen to gas.

After this step is has to be seperated with the Linde cycle.
https://en.wikipedia.org/wiki/Hampson%E ... inde_cycle
Cool it down, heat your home.
The liquid, compressed gas can be Autogas.

Then you can use the product
https://en.wikipedia.org/wiki/Autogas

Still no free energy, the way to this is different.

[agor95]

Joule-Thomason Effect

This procedure is called a throttling process or Joule–Thomson process.
At room temperature, all gases except hydrogen, helium and neon cool upon expansion by the Joule–Thomson process when being throttled through an orifice; these three gases experience the same effect but only at lower temperatures.

Minor point about hydrogen

Most liquids such as hydraulic oils will be warmed by the Joule-Thomson throttling process.

Interesting point about oil

Some members will remember the OU device that used oil in a rotating engine.

https://web.archive.org/web/20070304090 ... n.htm#_top

[agor95]

Current Electric to Hydrogen motors.
For Your Information

https://www.youtube.com/watch?v=f7MzFfuNOtY

This does not factor in AC Electrolysis of water within a car.

https://chemistry.stackexchange.com/que ... lysis-work

Electronic transitions (breaking of bonds) need energies in the UV, and here we meet bands that lead to photodissociation, e.g. at 166nm (taken from Wikipedia)

In the previous posts on this subject you will see lasers, electric change and high short term electric voltage was used.

There are references of heat generation using pulsed DC and the AC method states this did not happen.
Heat is generated when using DC Electrolysis.

Regards

[George1]

To agor 95 and to Georg Kunstler
----------------------------------------
Hi, guys.
1) First of all thanks a lot for the extremely interesting links you have sent to me. But the information here is too much and it will take some time to consider it carefully and assimilate it thoroughly.
2) As I can see you are inventors-enthusiasts just like us. So would be so polite you both to think over the possibility to join our team?
Looking forward to your answers.
Best regards,
George

[agor95]

Hi George1

Can you create a topic in the off topic section on joining your team?

Also get Scott to create a private group for your team?

Would you like to inform the members how many members are in your team?

Regards

[George1]

Hi agor95.
I perfectly agree with your suggestions. But I have to consult about this the other members of our team too.
Meanwhile you can have a look at the next post of ours.
Looking forward to your answer.
Best regards,
George

[George1]

To agor95
-------------------
Some computer problem appears here. I will send the promised post later.
Regards,
George

[George1]

Hi guys,
My colleagues and I have been extremely busy for the last 7 days and because of this we could not pay attention to besslerwheel.com/forum. We will consider carefully your last posts and will write our answers in the very nearest future.
Best regards,
George

[George1]

[quote="agor95"]Hi George1

Can you create a topic in the off topic section on joining your team?

Also get Scott to create a private group for your team?

Would you like to inform the members how many members are in your team?

Regards[/quote]
---------------
Hi agor95.
Please excuse my retardation.
1) It sounds interesting to create a topic in the off topic section. And what is the difference between the topics, discussed in the off topic section, and the topics, discussed in the general discussion section?
2) Who is Scott?
Looking forward to your answer.
Best regards,
George

[agor95]

Hi George1

Can you create a topic in the off topic section on joining your team?

Also get Scott to create a private group for your team?

Would you like to inform the members how many members are in your team?

Regards

Hi agor95.
I perfectly agree with your suggestions. But I have to consult about this the other members of our team too.
Meanwhile you can have a look at the next post of ours.
Looking forward to your answer.
Best regards,
George

We are waiting for you to answer questions?

To agor95
-------------------
Some computer problem appears here. I will send the promised post later.
Regards,
George

[George1]

Any comments, recommendations, objections? Any positive and constructive criticism is always welcome.
Best regards,
George

[George1]

Hi guys.
Please have a look at the first post of ours related to this topic.
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And after that please have a look at the book "Solved Problems in Physics", 2004, Volume 2, p. 876, solved problem 12.97. The author of this book is Prof. S. L. Srivastava (Ph.D.)
The same book can be found at the link https://books.google.bg/books?id=rrKFzL ... 22&f=false
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For your convenience I am giving below the text of the problem and its solution.
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12.97. In the electrolysis of sulphuric acid solution, 100 mg of hydrogen is liberated in a period of 20 minutes. The resistance of the electrolyte is 0.5 Ohm. Calculate the power consumed. Electrochemical equivalent of hydrogen is 1.044 x 10 -8 kg/C.
Solution: The power consumed is equal to 31.86 W.
Prof. S. L. Srivastava stops here his calculations.
(The related solution's set of equations is not given here in order to save time and space. This set of equations however can be found in the book or in the link above.)
--------------------------
The above solved problem has a potential which can be developed further. And here it is.
1) Let us calculate the inlet energy, that is, inlet energy = (31.86 W) x (1200 s) = 38232 Ws = 38232 J.
2) Let us calculate the current I. The current I is given by I = (m)/(Z x t) = 7.9 A,
where
m = 0.0001kg of hydrogen
Z = electrochemical equivalent of hydrogen
t = 1200 s
3) The Joule's heat, generated in the process of electrolysis is given by
Q = I x I x R x t = (7.9 A) x (7.9 A) x (0.5 Ohm) x (1200 s) = 37446 J = outlet energy 1.
4) HHV of hydrogen is 142 000 000 J/kg. Therefore the heat H, generated by burning/exploding of 0.0001 kg of hydrogen, is given by
H = (142 000 000) x (0.0001) = 14200 J = outlet energy 2.
5) Therefore we can write down the equalities:
5A) outlet energy 1 + outlet energy 2 = 37446 J + 14200 J = 51646 J
5B) inlet energy = 38232 J.
6) Therefore COP is given by
COP = 51646 J/38232 J = 1.35 <=> COP = 1.35 <=> COP > 1.
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Constant pure water and cooling agent supply could keep constant the electrolyte's temperature, heat exchange, mass and ohmic resistance, respectively.
Besides 0.0001 kg of hydrogen (and the related amount of the already split pure water) is small enough and can be neglected as a factor influencing the electrolyte's temperature, mass and ohmic resisitance.
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And one more interesting fact.
Literally the same solved problem can be found in an old Russian (still from the Soviet times) book "&#1057;&#1073;&#1086;&#1088;&#1085;&#1080;&#1082; &#1079;&#1072;&#1076;&#1072;&#1095; &#1080; &#1074;&#1086;&#1087;&#1088;&#1086;&#1089;&#1086;&#1074; &#1087;&#1086; &#1092;&#1080;&#1079;&#1080;&#1082;&#1077;", 1986, p. 130, solved example problem 71. The authors of this book are &#1056;. &#1040;. &#1043;&#1083;&#1072;&#1076;&#1082;&#1086;&#1074;&#1072; and &#1053;. &#1048;. &#1050;&#1091;&#1090;&#1080;&#1083;&#1086;&#1074;&#1089;&#1082;&#1072;&#1103;. In the Russian version the data is a little different, that is, time is 25 minutes, the amount of generated hydrogen is 150 mg, Ohmic resisitance is 0.4 Ohm and the calculated power is 37 W.
Russians also stopped their calculations at 37 W.
Our further development of the Russian version led to COP = 1.37, that is, we have again COP > 1.
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Therefore the text above unambiguously shows that it is a matter of exact experimental data which is in perfect accordance with theory. Because I cannot imagine that three highly qualified experts in physics (yet strongly separated by time, space and nationality) would have made one and same mistake three times in a row. This is impossible!
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Looking forward to your answers.
Regards,
George

[George1]

Any standard simple hydrogen generating electrolyzer can be used as a heater, which has efficiency/COP bigger than 1. It's evident!

[Georg Künstler]

Then we make this in the

https://de.wikipedia.org/wiki/Marianengraben

in very deep water.

The upgoing hydrogen, Oxygen can fill up a balloon, which will connected to a rope and a Generator generate power.

So we get Oxygen, hydrogen and electrical power in one go.

Nice idea, or ?

[George1]

To Georg Kunstler
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Hi Georg.
This is really a good idea! A perfect one! Any approximate calculations?
Regards,
George