A simple electric heater, which has efficiency greater than 1

[MrTim]

To MrTim and Tarsier79.
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1) A standard DC water-splitting electrolysis process takes place in your laboratory.
2) A direct current I flows through the electrolyte. This direct current I is equal to 1A, that is, I = 1A. (This is the reading of your standard working DC ammeter.)
3) The Ohmic resistance R of the electrolyte is equal to 1Ohm, that is, R = 1Ohm. (This is the reading of your standard working DC ohmmeter.)
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I am asking you PERSONALLY my question for the 4th time: How many Joules of heat per second (J/s) does the electrolyte absorb from the external environment?
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All members of this forum are looking forward to your PERSONAL answer for the 4th time.

Here is your FINAL and PERSONAL answer:

As listed on one of the sources on page 13, the efficiency of electrolysis is 87%. Therefore your equation is missing an important factor, corrected here:

(I = 1A) x .87 , meaning your efficiency is LESS THAN 1

In the future, when you present your equations, please include the efficiency of the electrolysis (x .87) in your calculations.
Failure to do so will result in your flawed arguments/results being ignored, so please quit wasting our time...

[Tarsier79]

Excellent suggestion Mr Tim.

[WaltzCee]

Maybe for their next trick they'll pull quarters out our ears . . .

ETA:

(I = 1A) x .87 , meaning your efficiency is LESS THAN 1

I would not mean to insult you, but you really are an obtuse asshole.

[PeterAX]

To MrTim.
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I would not like to insult you, but you are really an ignoramus in the field of electric engineering!
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Can you explain to all of us here in this forum what represents this EXTREMELY STRANGE mathematical expression "(I = 1A) x .87"? What is this? Current? Energy? Power? Something else?

[PeterAX]

Asking the same simple question for the 5th time: If I = 1A and if R = 1Ohm, then how many Joules of heat per second (J/s) does the electrolyte absorb from the external environment?
WRITE DOWN THE NUMBER OF JOULES! How many Joules? 1 Joule? 2 Joules? 3 Joules? 0 Joules? How many Joules?
Looking forward to your answer for the 5th time.

[Leafy]

If you insist that the electrolyte absorb 1J/s, then the solution would not gain any heat. But the video I shown have a temperature dropped. How would you explain this?

[WaltzCee]

I think I know, Leafy.

[Tarsier79]

OK. My understanding:

You supply an amount of power to the system.

Assuming the efficiency of electrolysis is 87%, that amount of power will be used directly for Hydrogen + oxygen production. The additional 13% will be divided in inefficiencies such as heat (the Joule effect), plus other reactions that occur depending on the electrolyte which may additionally produce or absorb heat.

Because electrolysis of water is an endothermic reaction, energy is pulled from the "heat" of the water. This cools the water to create Hydrogen and Oxygen. To me this also could mean that if your electrolysis was 100% efficient, and you could extract hydrogen heat at 100%, you could theoretically get an energy gain. This is because you use ambient temperature as an energy source.

The more inefficient your system, the more heat is produced.

I am asking my question for the 4th time: If I = 1A and if R = 1Ohm, then how many Joules of heat per second (J/s) does the electrolyte absorb from the external environment?
WRITE DOWN THE NUMBER OF JOULES!
Looking forward to your answer for the 4th time.

I cannot answer the question more simply. You have not given enough information. Even if you did, I do not understand the math enough, nor wish to spend the time to. I have an excerpt from the website I have already pointed out:
https://www.sciencedirect.com/topics/en ... c-reaction

It doesn't answer the heat required per L of Hydrogen.

[PeterAX]

To Leafy.
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A possible explanation could be for example either an unintentional or (most probably!) an intentional experimental error. Because many people (like Tarsier79 for example) do their best to save the law of conservation of energy. 

[PeterAX]

To Tarsier79.
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You demonstrate again a shocking ignorance!
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You have copied blindly a certain formula without understanding its essence! This formula does not contain (as its components) direct current I and Ohmic resistance R, you ignoramus! (Please excuse me, if I have insulted you. I am ready to apologize.) 

[PeterAX]

1) Asking the same simple question for the 6th time: If I = 1A and if R = 1Ohm, then how many Joules of heat per second (J/s) does the electrolyte absorb from the external environment? WRITE DOWN THE NUMBER OF JOULES!
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2) Besides how does this heat (which is absorbed each second by the electrolyte) depend on direct current I and on Ohmic resistance R? WRITE DOWN A FORMULA! 
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Looking forward to your answer for the 6th time.

[Robinhood46]

Waltzcee,
That looks like a good idea, if i could make a suggestion, maybe if you were to use a magical energy combiner you could increase the output.

[PeterAX]

1) Asking the same simple question for the 7th time: If I = 1A and if R = 1Ohm, then how many Joules of heat per second (J/s) does the electrolyte absorb from the external environment? WRITE DOWN THE NUMBER OF JOULES!
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2) Besides how does this heat (which is absorbed each second by the electrolyte) depend on direct current I and on Ohmic resistance R? WRITE DOWN A FORMULA!
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Looking forward to your answer for the 7th time.

[Leafy]

You’re asking people to choose your theory over experiment result. Don’t you think that is unfair?

[Tarsier79]

Besides how does this heat (which is absorbed each second by the electrolyte) depend on direct current I and on Ohmic resistance R? WRITE DOWN A FORMULA!

Ha ha, and I am the ignorant one.

You have copied blindly a certain formula without understanding its essence!This formula does not contain (as its components) direct current I and Ohmic resistance R, you ignoramus! (Please excuse me, if I have insulted you. I am ready to apologize.)

Its essence is there is an energy balance.

I am not insulted, nor do I need of an apology from someone who has to pretend he has a "team" and pretends to have understanding of electrical, chemical and mechanical engineering because he took general science in junior high.