The origin of the GRAVITATION.

[WaltzCee]

a) If you want to write a book you have to understand how it works.

b) What reimbursement are you talking about?

c) I wouldn't buy, I don't need.

d) For a real and functional model, you have to go through a design office, calculate the shapes and the pressures on the surfaces in depth. This is a job for fluid engineers, for shipbuilding. They have the qualified personnel to that.

a) I have a fair idea yet I'm always looking for tips.

b) I don't consider it reimbursement, more like the sales of an educational tool.

c) The working model would begin as a blank test bed used primarily to substantiate the points I make in the book. The user would ultimately build the model and could tinker with it.

d) Someone who designs and builds something that works is as qualified as necessary. So far that's a unicorn.

[Mikhail]

Write a book for high school students, let them practice calculating engines of various parameters - the weight of the concrete mass, the depth of immersion. It is also possible for students with calculations of all parameters of a real engine.

[WaltzCee]

Hello,

Does anyone understand how it works and check the arithmetic calculations of my perpetuum mobile ??

Write a book for high school students, let them practice calculating engines of various parameters - the weight of the concrete mass, the depth of immersion. It is also possible for students with calculations of all parameters of a real engine.

Yeah. I think there are enough high school texts. The folks at the M.U.D. have some very educated ones who have reviewed your patent with a fine tooth comb.

IMIO you need to take this idea to the next level. Have you managed to persuade anyone else about this idea?

[WaltzCee]

a) If you want to write a book you have to understand how it works.

. .. .. .

a) I have a fair idea yet I'm always looking for tips.

. .. .. .

I apologize. I thought you meant how to write a book. :) Admittedly I've never written one yet I think I'm up to the task. From what I've read the first step is to have something to say.

I'm always up for ideas on writing and publishing a book.

As far as understanding your idea, although I have a bit of an idea, I'm willing to accept the opinion of the brilliant people here and at the M.U.D. I have a very high regard for the technical opinion of some of the members here.

Analysis can take different forms. I can sort different American pennies by shaking them in my hand. I can also do it by dropping them on a surface and listening to their ring. I can also just look at the date.

The way I evaluate your idea is

• As well publicized its been
  and seen by very qualified & educated people
  yet hasn't moved beyond this stage in all this time

has a high probability of never escaping the mire of the M.U.D.

I don't think you understood what I meant. I want to sell an actual working model. It will be a kit. It will come with a money back guarantee.

The book will assert various postulates that can be immediately tested/proved. I don't plan on making claims I can't prove.

Too much of that has gone on for too long.

[Mikhail]

Yes. I think that there are working engines, but no one officially informed me about this. This is a very sensitive story. Prices for gas, oil, coal, etc., as well as stock quotes, may collapse. If someone has produced working engines, then he sits quietly and is silent.

Read here with google translate : http://vitanar.narod.ru/MSmer/MSmer.html

[WaltzCee]

I will not build anything, I have neither the means, nor the opportunity, nor the desire, nor the need for this, and I am too old for this. I have the energy I need, let those who need energy build the engines, for this I left them in free use.

Are you saying you make your own free electricity?

[Tarsier79]

This type of engine will not work.

For a real and functional model, you have to go through a design office, calculate the shapes and the pressures on the surfaces in depth. This is a job for fluid engineers, for shipbuilding. They have the qualified personnel to that.

You don't need to be an engineer to calculate forces here. Even a sheet of graph paper and a crayon can show why.

The force it takes to inflate the container to lift, is not overcome by multiplying containers. Connecting them via a tube will not solve the issue of greater pressures at depth. The displacement x force will equal the buoy rising under ideal conditions to the top. The force that is needed to overcome the pressure has to come from the force of the mechanism rotating around the bottom (and top), and does not come from any arrangement of weights or magnets that I can see. Forcing the container past the actuator/magnet/weight transition at the bottom will create a massive back torque this device will not overcome.

If Your system magically actuated the piston without back torque, you could install it on a simple immersed wheel and it would self revolve.

[Mikhail]

This type of engine will not work.

Did you check?

You don't need to be an engineer to calculate forces here. Even a sheet of graph paper and a crayon can show why.

The force it takes to inflate the container to lift, is not overcome by multiplying containers. Connecting them via a tube will not solve the issue of greater pressures at depth. The displacement x force will equal the buoy rising under ideal conditions to the top. The force that is needed to overcome the pressure has to come from the force of the mechanism rotating around the bottom (and top), and does not come from any arrangement of weights or magnets that I can see. Forcing the container past the actuator/magnet/weight transition at the bottom will create a massive back torque this device will not overcome.

If Your system magically actuated the piston without back torque, you could install it on a simple immersed wheel and it would self revolve.

Apparently you did not understand the principle of action.
The force needed to overcome the pressure comes from the force of the mechanism rotating around the base (and top) and this force drives the internal mechanism - mass + gas springs - which will produce the necessary force to move the piston. The file (via the link in the signature) clearly indicates and calculates the forces from water pressure on the piston and the forces that the internal mechanism produces. It also takes into account the energy for the float to bypass the lower and upper wheels and indicates that the energy does not depend on the trajectory, but only on height - this is the law of physics.
It won't create much reverse torque as the float goes around the bottom and top wheels because there is a similar float on the opposite side with the same weight balancing it.
Connecting the floats with a flexible hose has nothing to do with external pressure on the piston.
A wheel submerged in water with identical floats will not rotate because the left and right sides are balanced at the same time. In order for the engine to work, the floats must be in a larger and smaller volume for some time, working time, when they produce useful work / energy. This time is the time of their movement in a straight line.
I don’t seriously consider an engine with magnetic floats, except perhaps in the form of a toy. Magnets are expensive and this type of motor cannot produce much power. The gravity engine can, in proportion to the weight of the concrete ingots.

[Mikhail]

Are you saying you make your own free electricity?

No.

[Tarsier79]

You may have invested so much of yourself into this design that you have developed tunnel vision. It is the transition from non buoyant to buoyant that will create your sticking point, not it's orientation. This change costs. It's occurrence happens rotating around the bottom, and the float must force itself around against the action that expands the chamber. Rotation drives against the mechanism that expands the chamber, even if you don't see that is the case. I am afraid it is a 0 sum game you are playing.

[Mikhail]

Okay, let me explain differently. Without water, the engine is symmetrical, all floats are identical. What happens between points A-B and C-D is also symmetrical in weight. Symmetry is broken only under water as a result of the action of the force of Archimedes.
That's all you need to know. The imbalance occurs under the action of the Archimedes force. When the float is turned over, we need to raise the load of the blank to the height of its movement. It's all.
In the example, according to the link in the caption, the float produces work / energy at a distance of 4.5 m and 0.5 m is spent on lifting the load.
You see only one side of the engine at a time, forgetting the other. It is symmetrical and proportional.

[johannesbender]

The change in the volume of elements depends on the distribution of masses inside the device. Under the influence of gravity, the masses will change the volume of the elements, and the Archimedes force will cause the wheels (1) and (2) to rotate in accordance with the location of the elements in relation to the axes of the wheels (see Fig. 1). Additional images of sections of float elements are shown in Fig. 2 - 5.

When the magnetic float is turned over, the position of the control magnetic element relative to the stator changes (the stator rotates by 180°). Under the action of the opposite direction of forces, a change in the working volume occurs. The movable magnetic rotor is maintained in a certain constant position by external floats.

Method for calculating the engine with masses

The device uses gas springs (gas cylinders that are filled with nitrogen under pressure). In principle, these springs are identical to the parts used in cars to open and support the rear door of the car. Let us assume that the lower axle of the wheel is at a depth of 5.5 m (meaning the distance between the axles of the upper and lower wheels, since the depth at which the upper axle and the entire engine are located does not matter much). Gas springs must be selected based on the difference in the depths of the axles of the wheels. Let us assume that the axle of the upper wheel is at a depth of 3 m. The water pressure at this depth is approximately 0.3 kg/cm. If the weight of the mass is 100 kg, then the piston area will be 100 kg x 8 (coefficient) = 800 cm 2. Add 10 kg of weight to overcome friction. Thus, the working weight of the mass will be 110 kg. The area of ​​the float piston is 800 cm2. The pressure on the piston at a depth of 3 m is 800 x 0.3 = 240 kg. The piston presses on the lever, transferring to its end a force equal to 240: 2 = 120 kg. Thus, at the end of the lever, that is, on gas springs, we get 120 kg (Fig. 1, point B), we add the weight of the mass % 110 kg, from which 120 + 110 = 230 kg, directed vertically downwards. Thus, it is necessary to select gas springs (there are 2 in the example) with a force of 115 kg each. The mass, moving downwards under the action of weight (gravitational force) and pressure from the piston, will “compress” the gas springs, while the potential energy will accumulate in the compressed springs in the form of a pushing force. The path (length) of mass movement is 50 cm, therefore, the piston stroke is 25 cm, from where: the piston area is 800 cm 2 x 25 cm = 20,000 cm / cu, which equals 20 liters. This work will take place between points A and B (Fig. 1). The volume of the element will decrease by 20 liters. When the same element with which we started our example, in the process of moving (immersion) will be at the level (or almost at the level) of the axle of the lower wheel on the left side (Fig. 1, point D) at a depth of 8.5 m (5, 5 m + 3 m = 8.5 m), the water pressure will act on the piston (approximately 0.85 kg/cm2). Thus, the water pressure on the piston will be 680 kg (piston area 800 cm2 x 0.85 = 680 kg). In this case, the float, bypassing the lower wheel, will turn 180 °. In order to resist this pressure, each spring has 110 kg (mass weight) + 115 kg, from which: 115x2 + 110 = 340 kg directed vertically downwards. Given that the middle of the lever pushes the piston, a force equal to 340x2 = 680 kg will act on it. Thus, forces act from both sides, identical in size. In this case, at the top right, the piston will drop slightly below a depth of 3 m (water pressure will increase), and at the bottom left, it will drop a little higher (water pressure will decrease). With an increase in mass by 5 or 10 kg below (between points C and D, Fig. 1), under the influence of the weight of the mass and the force of the springs, the piston will move down, increasing the volume of the element by the same 20 liters. Of course, in order to release energy, it is necessary to slow down the rotation speed of the mechanism in order to reduce friction losses in water (it is known that friction losses when moving in water are proportional to the speed of movement). 1) under the influence of the weight of the mass and the force of the springs, the piston will move down, increasing the volume of the element by the same 20 liters

accordingly to your numbers , top right 3m bottom left 8.5m , the only thing i think you will find ,is slight air compression , just my opinion:

1.gif

click to see animation

[Mikhail]

This has nothing to do with the gravity engine and animation, even more so. The air has nothing to do with it at all, the air is not compressed, but goes into the float, which increases the volume at the same time as the float, which decreases in volume.

[johannesbender]

This has nothing to do with the gravity engine and animation, even more so. The air has nothing to do with it at all, the air is not compressed, but goes into the float, which increases the volume at the same time as the float, which decreases in volume.

if air was completely incompressible fluid , you still would not be able to increase the volume at 8.5 and decrease the volume at 3m , as shown , the opposite will happen:

2.gif

3.jpg

[johannesbender]

if the gas springs were placed to attach inside the "float" vessels and to the piston , and the levers connected/pivot to the inside of the "float" vessel, and the pistons to the levers:

MSmer_html_m5ddb8c84.png

air would slightly compress to some amount , and then transmit force to the top piston which has the lower pressure , in my opinion:

a.gif

and if it were an incompressible gas/fluid it would transmit most/all force from the lower piston under higher pressure to the upper piston which has lower pressure, my opinion:

b.gif

so i see no advantage top and bottom ,the top piston with lower pressure needs to have a far greater advantage over the lower piston which is under higher pressure ,to be able to move the bottom piston out and the top in.

considering the language not being very clear when translated , im sure one of these situations is enough to convince me, or at least stipulate that i don't see it .