1lb lift 3lb. Lever dynamics

[Tarsier79]

OK. So first, you need to accurately measure your weights. You need to also measure the weight of each arm of your pipes.

I think you would be better with a test wheel, and weights placed in position on that wheel instead of pipes.

Ideally, you want to start with a known balanced mechnanism. This means there is no bias to want to turn anywhere. Then add known weights to measured positions. Perform your test, measure the output.

For this to be OU, you need to get more out than you put in. The input is the dropping weight, the output is lifting weight + rotational energy. The parts we are interested in are the weight drop and lift over what vertical height.

[Leafy]

Ok

The heavy leg is .4lb
The right leg is .165lb
The 12 washers are .125lb
Long leg 15.25in
Short leg 8.5in

How much lift needed for unity?

[Tarsier79]

How long are the poles?
I can guess the angle of the poles.

[Leafy]

The poles are there to make sure the leg is at 45.

I calculated, the drop needed for unity is 1.176 inches. It takes 5 inches to reset, so the efficiency is about 20s. Can a lever be that inefficient?

But it occurs to me that it’s better to drop less height with more weight than less weight with more height. Because drop force depends more on mass than height.

Next, increase drop weight with shorter drop distance.

[Tarsier79]

What is the length of them?

[Leafy]

Uncut from factory 24inches each

[Tarsier79]

... And you cut them to about 12" and 6"? It looks from the images one is half the other.

[Leafy]

Ok

The heavy leg is .4lb
The right leg is .165lb
The 12 washers are .125lb
Long leg 15.25in
Short leg 8.5in

How much lift needed for unity?

No, the cut part is 15.25 and 8.5

[Leafy]

From 20% efficient to OU, it’s weird.

Required drop height for unity is .66 inches. I think I only used .25 inches. The more mass the more momentum.

https://youtu.be/r6T2aDiIlaU

[Tarsier79]

Suppose to add 10 on the heavy side and 6 on the right side.

I did it and it takes 5 inches to reset, but it’s a big increase in efficiency. Actually double the left suppose to double the right

Does this look correct? So using trig.(or an online triangle calculator) you can calculate each component, where it is resting, and where it is at reset. You could even put in in a spreadsheet to calculate for you.

[Leafy]

Never mind, the system remains 20% efficient. Seems like it eats energy rather than produced more.

[Tarsier79]

It most likely would.

Did you try swinging it like a 2SO?

When you drop the weight, it produces an impulse. It is traveling at full speed, trying to accelerate something that is stationary. A number of things can be done to improve efficiency, like a non linear mechanism like MT24, or just swing it: but that takes away the impulse.

Is the drawing correct? or you could correct any of the figures. Let me know if you want me to show the calculations as well.

Cheers

[Leafy]

Thx Tarsier,

I don’t see anymore improvement on this setup, so I’ll try to put the long leg on the light side to play with the time factor. Maybe less weight but more distance and time will trigger something new.

Cheers