Zeroing in on Bessler's wheel
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- eccentrically1
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Re: Zeroing in on Bessler's wheel
then don't include them. what is the location of your weights however your concept is supposed to work. Rings and rollers?
Last edited by eccentrically1 on Fri Feb 10, 2023 6:06 pm, edited 1 time in total.
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Re: Zeroing in on Bessler's wheel
Why do I get the feeling I'm being set up. Yes. At @ 3:00 they, the rollers fly outward in a blink of an eye or so. That's about 1/10 of a sec. or 100 milli seconds. I don't have a digital encoder to record position information or acceleration times or accelerometers to record the impact. However it's very fast, If that answers your question---------------------Sam
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Re: Zeroing in on Bessler's wheel
No, I'm not setting you up.
Can you post a pic or link to what your thing looks like?
Can you post a pic or link to what your thing looks like?
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Re: Zeroing in on Bessler's wheel
Sure, see Fletcher sim page 47. The flats are shown on a tangent, which is wrong. For it to work the flat has to be on a radius, as in the spoke of a wheel, on the right hand side of the ring, for CW rotation at 12:00------------------Sam
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Re: Zeroing in on Bessler's wheel
*
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Re: Zeroing in on Bessler's wheel
eccentrically1 wrote: ↑Fri Feb 10, 2023 7:54 pm The sim shows the cf problem at 30-40 rpm. It accelerates the rollers until they are merely part of the wheel (cart).They can't move at all, they're going the same speed as the wheel, not faster or slower. This only shows what would happen with cf with a motor. If you turn off the motor and start it with gravity (the rollers located at highest gravitational potential energy, the flats can be anywhere for maximum drop), they'll accelerate, (the cf helps accelerate one of them outward and the other two inward {bummer}, they lose that static PE, converted to motion, KE, then oscillate around the CoG that never lifts.
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Re: Zeroing in on Bessler's wheel
Well so much for sims!
Let me walk you through it. Once again the flat has to be on a radius. I don't know what you mean by drop, or lift, for that matter. After the wheel rotates 90 CW, the flat is now horizontal at 3:00, the rollers are thrown out to the rim of the casing. The wheel is now OOB, and the wheel will turn.
The reason is; the roller is now out farther, (2 inches for the old wheel), than the roller going up. This isn't some bull shit theory, I've already demonstrated the operation of it.
It really amounts to only one moving part. It's not complicated. It's not 3 dimensional calculus. I'm at a loss as to how to explain it to you or any one else for that matter-------------------------Sam
Let me walk you through it. Once again the flat has to be on a radius. I don't know what you mean by drop, or lift, for that matter. After the wheel rotates 90 CW, the flat is now horizontal at 3:00, the rollers are thrown out to the rim of the casing. The wheel is now OOB, and the wheel will turn.
The reason is; the roller is now out farther, (2 inches for the old wheel), than the roller going up. This isn't some bull shit theory, I've already demonstrated the operation of it.
It really amounts to only one moving part. It's not complicated. It's not 3 dimensional calculus. I'm at a loss as to how to explain it to you or any one else for that matter-------------------------Sam
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Re: Zeroing in on Bessler's wheel
The OOB is temporary because the leverage of the single roller, even at maximum radius, won't lift the other two rollers into overbalanced locations. The fact that they might be at minimum radius doesn't matter. Leverage alone won't add CF and gravity into a runner.
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Re: Zeroing in on Bessler's wheel
Sure it will, the leverage that is. The CF is used for shifting the weights only, no adding required. The weights are balanced going up, OOB going down-----------------Sam
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Re: Zeroing in on Bessler's wheel
CF won't shift all the rollers into overbalancing locations. It shifts one roller into OB (+torque), one roller into UB (-torque),and doesn't affect one roller.
Do you mean you've tested it ?This isn't some bull shit theory, I've already demonstrated the operation of it.
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Re: Zeroing in on Bessler's wheel
Well no, it can't shift them all at once. Only one at a time as they approach the 3: 00 position. Right, I tested it but with only two drums / two rollers. It won't work with just two. The reason is; they, the rollers, don't start driving the wheel until about 3:00. The best it can do is get back up to 9:00. The big thing is the weights are balanced going up; this I have verified.
I'm going to try it with four. All I know for sure is; two isn't enough. That's kind of what Bessler said, he had to add another cross-bar to get it going. On this point I agree. I still don't know for sure, that it is a runner. Just have to try it and see----------Sam
I'm going to try it with four. All I know for sure is; two isn't enough. That's kind of what Bessler said, he had to add another cross-bar to get it going. On this point I agree. I still don't know for sure, that it is a runner. Just have to try it and see----------Sam
Last edited by Sam Peppiatt on Fri Feb 10, 2023 9:37 pm, edited 3 times in total.
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Re: Zeroing in on Bessler's wheel
Yes, CF shifts them once as they approach 3. Not enough positive shifting going on to sustain OB. The roller experiencing a negative shift coupled with the roller not shifting at all is why it won't get past 9.
Even with additional rollers they still won't drive the wheel. B's one crossbar wheel got past 9 and then 12 etc. That's why another cross bar made it more powerful. If yours doesn't get past 9 with two or three, it won't with four.
But try it and see.
Even with additional rollers they still won't drive the wheel. B's one crossbar wheel got past 9 and then 12 etc. That's why another cross bar made it more powerful. If yours doesn't get past 9 with two or three, it won't with four.
But try it and see.
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Re: Zeroing in on Bessler's wheel
maybe you are right. Maybe the whole thing is a fucking piece of shit------------------------------Sam
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Re: Zeroing in on Bessler's wheel
I’m right, cf is not going to shift shit.