Scrap pad for testing .jpegs, .gifs etc.

[Senax]

delete

[Senax]

delete

[Senax]

https://drive.google.com/uc?export=view ... umXF_u9I5a

[Senax]

https://drive.google.com/uc?export=view ... umXF_u9I5a

http://www.besslerwheel.com/forum/posti ... b9d6e65ce5

[WaltzCee]

https://drive.google.com/uc?export=view ... umXF_u9I5a

http://www.besslerwheel.com/forum/posti ... b9d6e65ce5

This is strange Frank. Every time I click on this link you posted

• http://www.besslerwheel.com/forum/posti ... b9d6e65ce5

It takes me to a log in screen. Then when I login, it takes me to a screen with a post in progress.

Weird.

Welcome back.

[Senax]

Hello Senax

You will notice they have the same kinetic energy in the end.

Yes indeed.
They do have the same instantaneous kinetic energy in the end

But they do not have the same cumulative kinetic energy.
The low road mass, L has received more energy from the
cycloid slope reaction than the high road mass H has
received from the straight line slope reaction.

Showing this with maths is beyond my pay grade but I see it can be
demonstrated graphically by dividing the slopes into small cells and
adding up the contribution each cell makes.
It will be found that the total reaction energy input
is greater for L than for H.

Now if we return L up the H straight line slope
to the starting point, we have generated an energy surplus.

We have a closed circuit for L with a surplus of energy.

We have induced energy from the gravitational field.

[Senax]

Hello Senax

You will notice they have the same kinetic energy in the end.

Yes indeed.
They do have the same instantaneous kinetic energy in the end

But they do not have the same cumulative kinetic energy.
The low road mass, L has received more energy from the
cycloid slope reaction than the high road mass H has
received from the straight line slope reaction.

Showing this with maths is beyond my pay grade but I see it can be
demonstrated graphically by dividing the slopes into small cells and
adding up the contribution each cell makes.
It will be found that the total reaction energy input
is greater for L than for H.

Now if we return L up the H straight line slope
to the starting point, we have generated an energy surplus.

We have a closed circuit for L with a surplus of energy.
We have induced energy from the gravitational field.

Correction:
We have induced energy from the slope reaction with the gravitational field acting as a catalyst.

[Senax]

I'm just posting this image to check that I have remembered how to do it. 8-)

As you can see it show two pendulums, one following the other and released for a small angle.
I suppose on might call it a sub 360° degree pendulum.

I shall be discussing its relevance in subsequent posts.