Robert,
You figures of 38 pounds at six feet leaves me to ponder the following.
Is the six foot lever actually 12 feet and balanced so that its weight is not included? Or is the lever weighed and then deducted for true Net? The latter we leave me to question the fact that half the length of the lever is supported by the axle.
Not being a math person can this be stated the same as 6.333 foot pounds of torque?
Is this figure based on a static test such as resting the lever on a platform floor scale? Or is it a dynamic figure including inertia and CF forces at a given RPM? If it is dynamic then what is the given RPM?
What! you don't like me anymore. :-)
Ralph
Bessler Wheel Math
Moderator: scott
re: Bessler Wheel Math
Ralph
It would be dynamic.
It would equal the force that 38 lbs. exerts on a 6 ft. arm, like I said.
The rpm would be 26,
I still think u r OK...
It would be dynamic.
It would equal the force that 38 lbs. exerts on a 6 ft. arm, like I said.
The rpm would be 26,
I still think u r OK...
Robert (The Carpenter's Boy)
There's never time to do it right the first time, but there's always time to do it over again.
There's never time to do it right the first time, but there's always time to do it over again.
re: Bessler Wheel Math
On what do you base these numbers, Robert?
>were about 6 ft from the wheel's axle.<
That doesn't matter, what matters is the radius differential, assuming digital movement at 12 and 6oc. With 28.7W and 4lb weights for the Merseburg wheel, I find (the hypothetical!) Δr to be about six inches.
>were about 6 ft from the wheel's axle.<
That doesn't matter, what matters is the radius differential, assuming digital movement at 12 and 6oc. With 28.7W and 4lb weights for the Merseburg wheel, I find (the hypothetical!) Δr to be about six inches.
Disclaimer: I reserve the right not to know what I'm talking about and not to mention this possibility in my posts. This disclaimer also applies to sentences I claim are quotes from anybody, including me.