Cosmic Energy Electricity Generators

[Oystein]

I belive the error is easy to pinpoint !

As the whole confusion seems to be that the tension Centrifugal / Centripetal + F from mass is used as the force to calculate the work done.
Meaning that your theory indicates that we (equals to) "add mass to the weight" because the tension increases (centrifugal/centripetal) when there is extra energy added to the swing on one half (or part of) the swing...

This is not right, as the "Lead out work/energy" should be calculated from the very same d (distance) as the tension in the tension-vector is calculated from. (This distance do not change)
Any number multiplied by 0 becomes 0
Work is calculated from both force and distance !
(But the respective correct forces and distances, and no mix-ups ;-)

This is equal to lifting or pushing a compressed spring in a box.
Much tension and force involved, but no OU !

Best
Oystein

[ltseung888]

To Oystein and others who might have forgotten Physics 101,

Let me start with Physics 101. Use the diagram below. P is the pivot of the Pendulum. The Red Circle represents the Weight of the Pendulum Mg (60Kg). When we pull with a constant horizontal force F(10Kg), the Red Circle should move to the RHS. When should it stop?

Physics !01 tells us that it stops when there is an equal and opposite force opposing it. This equal and opposite force must be from the horizontal component of the tension in the string T1. In other words, we get the equation
T1 x sin(a) = F Â…Â…Â…Â…Â…Â…Â…Â…Â…Â…Â…Â…Â…Â…Â…Â…Â….(1)

The Red Circle at the new displayed position is stationary (the instant before we let go of the Swing). The Vertical Forces must be at equilibrium, this means:
T1 x cos(a) = Mg Â…Â…Â…Â…Â…Â…Â…Â…Â…Â…Â…Â…Â…Â…Â….Â….(2)

The Law of Parallelogram of Forces demands that the Resultant Force of F and Mg be represented by the diagonal X as shown. X must be equal and opposite to T1. This means
Tan(a) = F/Mg Â…Â…Â…Â…Â…Â…Â…Â…Â…Â…Â…Â…Â…Â…Â…Â…Â…Â…..(3)

These three equations are from Physics 101. If they are wrong, the foundation of Physics and NewtonÂ’s Laws are wrong. They MUST be right.

Once you accept the above analysis, the rest is strictly mathematics.

(1) The angle a is given by tan(a) = 10/60 or 9.48degrees.
(2) The horizontal energy is F x Length x sin(a) =1.64703Length (in Newton-meters)
(3) The vertical energy is Mg x Length x (1-cos(a))=0.819411Length (in Newton-meters)

In other words 1.64703 units of supplied energy (horizontal) Leads out 0.819411 units of FREE energy (vertical)

The coefficient of over unity (COU) = total output energy / supplied energy =(1.64703 + 0.819411)/1.64703 =1.497508 =1.5 approximately!

Note that 2 units of Horizontal Energy Leads Out 1 unit of Vertical Energy approximately. All these 3 units of energy are stored or conserved in the Pendulum System. If the system is over 66.7% efficient, the system can supply FREE gravitational energy.

[LustInBlack]

If you are serious (I doubt it) and your math is true, and according to what you say, it must be already instored in the fundation of physics..

Then why the simulation doesn't work !?

Because you are wrong.


If, by any chance, you are not wrong.. Then your DisRespected rating shows your problem . You came here, didn't try to make yourself any reputation, you just don't care that everybody hates you . Why do you think we don't give a shit!? .. Because you didn't make yourself known to us .. You did like every spammer, scammer and bot did; Talk bullshit repeating itself in a closed loop trying to impress and trying to get attention with stupid delay (In august 3d blablabla) .. Are you fucking stupid or stupidly insane!?

You are really getting on my nerve, your claim, as improbable it may be, just need to be considerate anyways, that's why I am here trying to get IT .. but there is no IT ..

I repeat it, since it's the trend of this thread, repeating always the same thing : You don't have anything to show .. Your "THEORIES" by your own acknowledgment, they are THEORIES, you don't show any answer, any real world data analysis, or any real world machine ..

Come here, if you have the machine and it's working, you shouldn't have any problem to pay the plane ticket to get known as a real inventor.. COME HERE, I'll make a video of your working prototype and make yourself known as the real inventor..

What do you think of that offer?! .. Come and show us ... I'm sure we can arrange something for you to show us, your marvelous machine ..

If your problem is money, then buy a quick and cheap webcam, you can get one for under 30$ and plug it in your PC and record... If you don't know how (with your degree), then I'll explain to you how to do it.. Then with that camera, you film your working machine at every angles during at least 1 hour of work..

That would be concrete something.. Not useless theories..
You are good at theories, but you don't show anything usefull .. So what's your problem!? .. Are you incredibly stupid or what!? ... This thread is looping itself in and out .. You don't show anything..

Can you take us seriously as a group!? .. Because your reputation just show us that you don't care about us.

[Tinhead]

Once you accept the above analysis, the rest is strictly mathematics.

(1) The angle a is given by tan(a) = 10/60 or 9.48degrees.
(2) The horizontal energy is F x Length x sin(a) =1.64703Length (in Newton-meters)
(3) The vertical energy is Mg x Length x (1-cos(a))=0.819411Length (in Newton-meters)

In other words 1.64703 units of supplied energy (horizontal) Leads out 0.819411 units of FREE energy (vertical)

The coefficient of over unity (COU) = total output energy / supplied energy =(1.64703 + 0.819411)/1.64703 =1.497508 =1.5 approximately!

Note that 2 units of Horizontal Energy Leads Out 1 unit of Vertical Energy approximately. All these 3 units of energy are stored or conserved in the Pendulum System. If the system is over 66.7% efficient, the system can supply FREE gravitational energy.

Sorry, I need some more explanations, somewhere I'm missing something.

So by investing 1.64 units in horizontal direction we get 0.81 units of 'free' vertical energy. How do I get the 1.64 back and at the same time, how do I 'extract' the 0.81 as usable energy? Otherwise it would be quite a bad deal :)

Cheers,
Rainer

[ken_behrendt]

Mr. Tseung...

You state:

(1) The angle a is given by tan(a) = 10/60 or 9.48degrees.
(2) The horizontal energy is F x Length x sin(a) =1.64703Length (in Newton-meters)
(3) The vertical energy is Mg x Length x (1-cos(a))=0.819411Length (in Newton-meters)

I think the problem we are having has to do with your expression (2) for the "horizontal" energy of the weight. Most people here would say that the weight does not have any horizontal energy stored in it and that all of the weight's energy consists of its "vertical" energy. You are saying that there are two types of energy possessed by the weight. But how could this be?

Where did you get the mathematical expression for the "horizontal" energy of the weight? I have never seen an expression like that before. However, I have seen an expression for what you call the "vertical energy" of the weight. That is similar to:

ΔPEgrav = mgΔh

where, for the pendulum you show, Δh = Length (1-cos(a))


I still think that you have mistakenly added energy to the pendulum which is not really there...mainly the energy you call "horizontal" energy.



ken

[Wheeler]

Dear Mr.ltseung888
I do not know if you are playing a game with the members here or not.
However if you are sincere, I will let you know that I have found a way that a pendulum can be used to create torque.
Now if you wish to continue your testing of the minds of the people who want to know something, this is ok.
However I think it would be good advice to now place a very powerful statement on the forum.
This will indeed act as a lead for ones who reach out for knowledge.

[Michael]

Ken, you are right. Lust, you are definitely right. Rainer you are right, Thomas you are right. Oystein you are right. Everybody is right except Mr. ltseung888 who is definitely wrong. Why don't you quit wasting everybodys time, either show a working machine or make with the sales pitch.

[ltseung888]

To Tinhead and ken_behrendt,

Sorry, I need some more explanations, somewhere I'm missing something.

So by investing 1.64 units in horizontal direction we get 0.81 units of 'free' vertical energy. How do I get the 1.64 back and at the same time, how do I 'extract' the 0.81 as usable energy? Otherwise it would be quite a bad deal :)

Where did you get the mathematical expression for the "horizontal" energy of the weight? I have never seen an expression like that before. However, I have seen an expression for what you call the "vertical energy" of the weight. That is similar to:

Code: Select all

ΔPEgrav = mgΔh

where, for the pendulum you show,

Code: Select all

Δh = Length (1-cos(a))

I put the reply to both of you in the same post because they are essentially the same. See the attached diagram. The diagram shows the arc of the Swing of the Pendulum.

The Horizontal Displacement is dX. The equation is
L x sin(a) = dX

The Vertical Displacement is dH. The length of Y is L x cos(a)
Thus dH = L – L x cos(a)
dH = L(1-cos(a))

Hope this fills the gap in the Mathematics. There are different ways to extract the lead out energy. My post on Wed Aug 02, 2006 9:41 am described one example.

[rlortie]

Not being into math as most of you know, for me the following quote taken from the above attachment "Parallelogram of force jpg" says all I need to know.

Parallelgram of Force Analysis on the Swing pulled to one side before letting go (no motion yet)

Where does the force come from to pull to one side before letting go. Is it the same force used to remove a magnet from the side of my refrigerator?

Ralph

[racer270]

Parallelgram of Force Analysis on the Swing pulled to one side before letting go (no motion yet).......lol

There are different ways to extract the lead out energy.

To Oystein and others who might have forgotten Physics 101,


Let me start with Physics 101. Use the diagram below. P is the pivot of the Pendulum.

[scott]

LOL that's pretty funny Gordy. :-)

As far as this thread goes I hope one of two things happens very soon:
1. Mr. Tsueng comes out with a working model
or
2. The reputation system does its job

I decided not to download the "theory" document because everytime I Open a Word document that someone attaches on this board, it tends to contaminate my current Word Template

Ken, that is because you don't know how to use Word, not because of any problem with the board.

Thanks for changing the format from .doc to .pdf. But, something is wrong. I can not seem to complete a download of your .pdf file. Are .pdf files allowed in attachments to posts on this board?

Again, please understand, there is nothing wrong with the board. There is, however, a problem with your browser or your acrobat reader.

It's called "user error."
-Scott

[LustInBlack]

I think the point is definitive, Tseung doesn't even reply to my questions or any confrontations ..


If I could, I would vote disrespect this user again ..

[ltseung888]

To LustInBlack

Come here, if you have the machine and it's working, you shouldn't have any problem to pay the plane ticket to get known as a real inventor.. COME HERE, I'll make a video of your working prototype and make yourself known as the real inventor..

What do you think of that offer?! .. Come and show us ... I'm sure we can arrange something for you to show us, your marvelous machine ..

We are planning to come to St. Louis for the Renewable Energy Conference in Oct. 10-12. There will be working prototypes from at least 5 inventors. One of them is already in USA. The working prototypes with commercial value will have the working principle explained but the inventors would not take apart their prototypes.

After finding this forum, I decided to take on the challenge of breaking the secret of the Bessler Wheel. Now I have revealed the secret theoretically, two teams have decided to actually build it with variations. We are confident that the “toys” can be built well before Oct. The details of these “toys” will be revealed to the World with no reservation. (Ken is right that the ppm mystery will be totally resolved before the end of this year.)

So far the theory has helped over a dozen inventors with “working or partially working perpetual motion machines” to explain or improve their inventions in China.

My offer is for you and/or some one in your group to come to St. Louis in Oct. If you do not want to participate in the Conference, I can arrange to show the working prototypes either before or after the Conference. The “toy” prototypes will be left behind in USA for the entire World. The detailed arrangement is being worked out. I had to admit that this forum helped me in the dry run. I would not have found the many claimed working ppm devices in USA without the useful links from this forum.

I only hoped that one of the respected addicts of this forum could follow the mathematics.

[LustInBlack]

The working prototypes with commercial value will have the working principle explained but the inventors would not take apart their prototypes.

Why !? If they are left behind ?!

[cw]

...I only hoped that one of the respected addicts of this forum could follow the mathematics.

I think the "respected addicts" have given your mathematics all the consideration deserved. No doubt, they've also hoped that you would either put up, or STFU by now. Same old sh**, different day.