Idea I had since elementary school

[preoccupied]

For a 2x2 right angle with the same weight at each end One machine balances at 45 degrees from the fulcrum on both sides.

left side 1.88+.84 =2.72 and .68+1.81=2.72
Two machines balance at 67.5 degrees from the fulcrum for the first machine's left side.

left side 1.98+1.21+.52=3.71 and .26+1.58+1.93=3.77 right side
3 macines balance at 82.5 degrees from the fulcrum on the first machine's left side.

4 machines pass 90 degrees from the fulcrum from the first machine on the left side.
left side 2+.26+1.41+.77=4.44 and 0+1.41+1.98+1.85=5.24 right

One weight can be reloaded. This is amazing but now I need to know how to take the reloaded weight and put it back into the system and what kind of system would it be going back to? Should I allow the weights to balance themselves out before the weight gets back to the next lever or should I make the weights stay put somehow? Tune into the next post for the thrilling conclusion. The math about the weight being able to be reloaded should be correct. Somehow this much more simple design works and the more complicated ones do not.

[preoccupied]

I want to calculate as if the the levers are blocked in place as the weight rolls down the ramp because I want the weight to go to a right angle. I don't want the angles to change by allowing it to balance out. The remaining 3 machines are at 7.5 degrees 22.5degrees 45 degrees and the fourth weight will be at 0 degrees.
+30 degrees left side 1+1.21+1.21+1.93=5.35 and 1.73+1.58+1.58+.51=5.4
It travels only 30 degrees which brings the farthest right angle weight to 75 degrees and then 52.5 37.5 and 30 degrees.

I have to add a fifth machine.
+6 degrees left side .21+1.18+1.38+1.7+1.98=6.45 and 1.99+1.62+1.45+1.04+.31=6.41
81 degrees, 58.5 43.5 36 6 degrees
I have to add a sixth machine.
+7 degrees left side .24+.45+1.36+1.54+1.82+1.99=7.4 and 1.99+1.95+1.46+1.27+.83+.07=7.57
88 degrees, 66.5, 50.5, 43, 13, 7 degrees
I have to add a seventh machine.
+2 degrees 2+.07+.31+.52+1.41+1.59+1.86=7.76 and 0+1.99+1.97+1.93+1.41+1.22+.73=9.25
A weight is reloaded twice with only seven machines!

more calculations to come

[Tarsier79]

I think the horse is dead, and whipping it isn't going to help.

So, by dropping 5 weights you can lift 2 up?... doesn't sound very efficient to me.

Do you agree, each mechanism has a COM drop. If weight is constantly falling, (which it always does, and your calcs seem to show it as well) can you expect to reset an entire system? The reset is lifting all the weight that has dropped to its original height.

[preoccupied]

The right angle multiple machines will eventually come into balance because the angles keep changing and eventually the angles will be at even distances enough to balance despite adding more machines.

[Tarsier79]

!

As far as I am concerned, that is the case for all mechanisms. If one doesn't work, then neither will 10, or 100. But I am sure there are people here with a differing opinion on that.

[preoccupied]

I've been very silly in this post. I've been chasing levers and I've been largely wrong in my pursuit because of simple lack of understanding of physics. The swastika looks like it would create mechanical advantage but shouldn't according to mechanical rules. The guy with the torque wrench is taking a long time to let me borrow it.

[Mark]

You're waiting to borrow some guys wrench ?
Seriously ??
click this link