The summary of my latest studies
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re: The summary of my latest studies
Come on daanopperman........The Mouth?????
meChANical Man.
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"All things move according to the whims of the great magnet"; Hunter S. Thompson.
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"All things move according to the whims of the great magnet"; Hunter S. Thompson.
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Re: re: The summary of my latest studies
Yes, I was searching for milk and you know how close the "F" key is to the "k".justsomeone wrote:Quote from Nic.
"paddles from behind". Think I may have inadvertently seen that movie on youtube when adult content filter was down.
Come on Nic........Inadvertently?????
If you think you have an overunity device, think again, there is no such thing. You might just possibly have an unexpectedly efficient device. In which case you will be abducted by MIB and threatened by aliens.
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re: The summary of my latest studies
May be, my signature said the true: I suggest here a very simple explanation of the Bessler concept (just a suggestion).
All we have been always surprised by the length of the Bessler's wheels axle.
In the drawing below this axle is in red, and because the own weight of the wheel, it has a curved shape
The consequence is important: the wheel itself is a kind of pendulum oscillating on the small red circle (like shown at the right side).
The COG (the black dot) can move on this small circle.
Now, let's suppose there is a mechanism prohibiting this COG to overpass the 06:00 vertical line (like indicated by the arrow), we win!
This is the mix of the 'chaotical wheel' and the 'hamster concept'.
http://www.besslerwheel.com/forum/files ... amster.gif
http://www.besslerwheel.com/forum/files ... wheel3.jpg
http://www.besslerwheel.com/forum/files/quad_fast.gif
At this level the big question is: how to limit the path of the COG, the wheel being suspended (therefore free)?
I have an idea about the way: a preloaded asymmetrical torque applied to the main axle thanks a giant spiral spring (remember the torsion bars)
(this being confirmed by the fact that Bessler always took care do not reverse the rotation).
edited:
Another confirmation is the impossibility for the Bessler's wheel to roll on the floor by itself (the principle cannot be applicable anymore) and the need for a full relocation (including the pillars)
All we have been always surprised by the length of the Bessler's wheels axle.
In the drawing below this axle is in red, and because the own weight of the wheel, it has a curved shape
The consequence is important: the wheel itself is a kind of pendulum oscillating on the small red circle (like shown at the right side).
The COG (the black dot) can move on this small circle.
Now, let's suppose there is a mechanism prohibiting this COG to overpass the 06:00 vertical line (like indicated by the arrow), we win!
This is the mix of the 'chaotical wheel' and the 'hamster concept'.
http://www.besslerwheel.com/forum/files ... amster.gif
http://www.besslerwheel.com/forum/files ... wheel3.jpg
http://www.besslerwheel.com/forum/files/quad_fast.gif
At this level the big question is: how to limit the path of the COG, the wheel being suspended (therefore free)?
I have an idea about the way: a preloaded asymmetrical torque applied to the main axle thanks a giant spiral spring (remember the torsion bars)
(this being confirmed by the fact that Bessler always took care do not reverse the rotation).
edited:
Another confirmation is the impossibility for the Bessler's wheel to roll on the floor by itself (the principle cannot be applicable anymore) and the need for a full relocation (including the pillars)
I cannot imagine why nobody though on this before, including myself? It is so simple!...
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re: The summary of my latest studies
Dear eccentrically1,
I'm afraid you shall follow the advice of Ralph: don't be so abrupt in your assumptions.
You are right if the bob of the pendulum is solid and the fulcrum fixed.
What about if the bob includes a mouse moving inside on a chaotical manner and if in the same time the arm of the pendulum has a clutch acting like explained above?
In this case the key is the displacement of the fulcrum in accordance with the motion of the mouse.
I'm afraid you shall follow the advice of Ralph: don't be so abrupt in your assumptions.
You are right if the bob of the pendulum is solid and the fulcrum fixed.
What about if the bob includes a mouse moving inside on a chaotical manner and if in the same time the arm of the pendulum has a clutch acting like explained above?
In this case the key is the displacement of the fulcrum in accordance with the motion of the mouse.
I cannot imagine why nobody though on this before, including myself? It is so simple!...
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re: The summary of my latest studies
Dear eccentrically1,
You forget to take in account the rolling motion of this shaft inside the internal rim of the bearings located in the pillars.
edited:
For a better understanding, the same principle is described here:
http://www.besslerwheel.com/forum/viewt ... 7532#57532
http://www.besslerwheel.com/forum/viewt ... 1364#71364
I guess you are too much optimistic.you wrote:It's not that complicated
You forget to take in account the rolling motion of this shaft inside the internal rim of the bearings located in the pillars.
edited:
For a better understanding, the same principle is described here:
http://www.besslerwheel.com/forum/viewt ... 7532#57532
http://www.besslerwheel.com/forum/viewt ... 1364#71364
I cannot imagine why nobody though on this before, including myself? It is so simple!...
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re: The summary of my latest studies
path-finder ,
In your drawing with the bent shaft . Start off with balanced weights on a shaft to be able to be moved oob , each weight has a pivot and a hook/foot/bracket to be manipulated to cause oob at 12 and at 6 . In the normal position the weights are all central and balanced , no oob . Now we add the wheel , the weight of the wheel will cause the 12 and 6 weights only to go out of balance . If the wheel weighs 100 kg and each of the working weights weigh 1kg each you have if you move 2x top and 2x bottom 116 kg 's to move 4kg . As in your sketch the wheel must be able to float on the shaft , IOW it to must be able to be balanced when sitting on the 4 working lifted weights .
In your drawing with the bent shaft . Start off with balanced weights on a shaft to be able to be moved oob , each weight has a pivot and a hook/foot/bracket to be manipulated to cause oob at 12 and at 6 . In the normal position the weights are all central and balanced , no oob . Now we add the wheel , the weight of the wheel will cause the 12 and 6 weights only to go out of balance . If the wheel weighs 100 kg and each of the working weights weigh 1kg each you have if you move 2x top and 2x bottom 116 kg 's to move 4kg . As in your sketch the wheel must be able to float on the shaft , IOW it to must be able to be balanced when sitting on the 4 working lifted weights .
re: The summary of my latest studies
Here is the link to the thread were I first discussed 'tapered bearings in 2005; http://www.besslerwheel.com/forum/viewt ... ic+balance
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re: The summary of my latest studies
I suspect this device can do an excellent job:
http://www.youtube.com/watch?v=gg-QCagnJcM
http://www.youtube.com/watch?v=gg-QCagnJcM
I cannot imagine why nobody though on this before, including myself? It is so simple!...
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re: The summary of my latest studies
PF, I find that this type of device doesn't behave quite as in the animation of something quite similar you have pointed to above.
Edit : I adamantly refuse to apologize for the welding; only had damp 3 mm rods and was working in semi darkness.
Edit : I adamantly refuse to apologize for the welding; only had damp 3 mm rods and was working in semi darkness.
If you think you have an overunity device, think again, there is no such thing. You might just possibly have an unexpectedly efficient device. In which case you will be abducted by MIB and threatened by aliens.
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re: The summary of my latest studies
Dear nicbordeaux,
Looking at this animation above, you forgot your X-rays glasses.
Inside the lower part of the device (culbuto?) there is a bowling ball.
Looking at this animation above, you forgot your X-rays glasses.
Inside the lower part of the device (culbuto?) there is a bowling ball.
I cannot imagine why nobody though on this before, including myself? It is so simple!...
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re: The summary of my latest studies
Dear PF, my experience with balls sliding in devices whether on rails or not can't be synchronized, so the reaction foces bring the device to a halt. But who knows.
What is amusing with that particular device is that if it has a slight weight bias to one end and a protusion each end terminated with a piece of rubber which bounces off the ground, it will travel along the floor in the direction of the heaviest end.
What is amusing with that particular device is that if it has a slight weight bias to one end and a protusion each end terminated with a piece of rubber which bounces off the ground, it will travel along the floor in the direction of the heaviest end.
If you think you have an overunity device, think again, there is no such thing. You might just possibly have an unexpectedly efficient device. In which case you will be abducted by MIB and threatened by aliens.
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re: The summary of my latest studies
Dear eccentrically,
An useful test (java plugin required):
http://www.elmer.unibas.ch/pendulum/rpend.htm
First stop the animation.
Drag the bob for a vertical position of the pendulum.
Then set the values:
length = 1
damping = 0.25
amplitude = 0.5
frequency = 0
And start the animation (nothing shall move, because the null speed).
Increase slowly the frequency to 0.5
In relation with the curved shaft above: the small rod (in black) is supposed to be the radius of this curvature.
An useful test (java plugin required):
http://www.elmer.unibas.ch/pendulum/rpend.htm
First stop the animation.
Drag the bob for a vertical position of the pendulum.
Then set the values:
length = 1
damping = 0.25
amplitude = 0.5
frequency = 0
And start the animation (nothing shall move, because the null speed).
Increase slowly the frequency to 0.5
In relation with the curved shaft above: the small rod (in black) is supposed to be the radius of this curvature.
I cannot imagine why nobody though on this before, including myself? It is so simple!...
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