NEWS FLASH!! Fcdriver has a working wheel!!!!

[Grimer]

...

Where does the device get its input energy is DEBATABLE!!!

Raj

I believe it gets its energy from the 3rd derivative of displacement with respect to time. (assuming it's not a fake as Al Setalokin suggests - but he is always a cynic)

[Fcdriver]

Replace the spring with a lever, from the video. A weighted lever. With a bearing to reduce friction a cam instead of the crank, use multiple arms.a weighted lever does not change in force as the spring would tighten. It is more constant.

[Grimer]

The pin driving the spring must be about 90° out of phase with the effective pendulum.

If nothing else it gives one a great idea how to transfer energy from a high speed to a low speed region of the pendulum.

Since there's a rational explanation I think it's too much of a coincidence for it to be a fake. The builder obviously has no idea why it works or where the energy to keep it going comes from.

[Grimer]

Replace the spring with a lever, from the video. A weighted lever. With a bearing to reduce friction a cam instead of the crank, use multiple arms.a weighted lever does not change in force as the spring would tighten. It is more constant.

Good idea. I suspect the spring characteristics change with time and the thing becomes detuned which will make the builder think he hasn't really harvested gravity.

Ultimately one would have some kind of feedback system to keep it in tune.

Edit: Although, thinking about it I think the response time of a weighted lever might be too slow.

[Fcdriver]

Bounce or float becomes a problem at higher speeds, the lifting has to be slight, not to cause bounce, and not relieve 100% of the downward force. The pushing down further from center gives mechanical advantage, while the lift is divided by the degree turns, and the incline plane(cam)and the lifting is done slower reducing force. Using a class one lever for lift, and a class three lever for the down stroke, but all on the same arm.

[Fcdriver]

http://thecraftycanvas.com/library/onli ... em-solver/

This can be used to calculate the cam, and the amount of force applied against rotation, vs lift

[Fcdriver]

http://www.engineersedge.com/calculator ... vers_1.htm

This can be used to calculate the leverage pushing down on the wheel and the amount of force being applied to the cam.

[justsomeone]

How about posting a simple sketch?

[Grimer]

I'm going to pinch the idea for my pendulum.

The beauty is that one doesn't even have to get the pendulum over the top.
All one has to do is show the pendulum rises higher with the spring in action than on its own.

As Eric says, The rest is just pure engineering.

[ME]

I'm going to pinch the idea for my pendulum.

I've dumped the formula into my own integral-solver (6th derivative test-version), so I should have more accurate values for such an ideal pendulum in unstable equilibrium.

As a weight is pushed by some spring, it would probably push back on the wheel (because of inertia of the pendulum bob weight). One can try to counteract by making the wheel more heavy, but that problem still remains and the pendulum would most probably no longer act like a stand-alone pendulum - just some unstable weight on a wheel.
And even if I understand wrong and it will be spring-pushed, it will contract at some unfortunate point later on.
I think I'm interested when it can push at 9 and contract at 3.

How about posting a simple sketch?

Agreed.

[Fletcher]

FCD ... what you are proposing is a method to separate the Inputs and Outputs from a machine so that they are discrete i.e. breaking the Law of Levers and basics of Machines for eons.


e.g. The currently accepted situation of machines or mechanisms is ...


Using Archimedes Law of Levers, proven by trigonometry. N.B. assuming no energy losses to system.


Force x Velocity into a machine (Input) equals the Force x Velocity out (Output).


Power = Force In x Velocity In (Input) = Force Out x Velocity Out (Output) ...


In terms of the Speed Ratio:


Ideal Mechanical Advantage (IMA) = Force Out / Force In = Velocity In / Velocity Out


IOW's ... Force can be multiplied by using a lever (any class) but the trade off is in the displacement seen in Velocity of the lever where Forces are felt. Simply, a small input Force can cause a large Force output but the input Force must be applied over the reciprocal in terms of distance/displacement.


Best of luck and I really do hope you have something novel to show !

[Fcdriver]

http://www.robotpark.com/academy/roboti ... ms-levers/

http://www.physicsclassroom.com/class/n ... Second-Law

Nope follows and proves them right, only disproves Helmholtz's I only prove that a connection between linear movement and rotation movement, does not have to be circular. By using a wheel as multiple pivot points, as a transfer device.

[Fletcher]

Like many have said .. I await the diagram (and video) instead of the words. No disrespect intended.

Still hope you are correct however and have found a work-around that kicks Law of Levers for touch. And that shows that MA x SR =/= 1.0 (Ideal)

[Grimer]

http://www.robotpark.com/academy/roboti ... ms-levers/

http://www.physicsclassroom.com/class/n ... Second-Law

Nope follows and proves them right, only disproves Helmholtz's I only prove that a connection between linear movement and rotation movement, does not have to be circular. By using a wheel as multiple pivot points, as a transfer device.

Sounds good to me. “Lay on, Macduff, and damned be him who first cries ‘Hold! enough!’�. :-)

[rlortie]

Fcdriver has done a fine job of posting links regarding leverage. But when asked for the output or torque of his machine, he answers with how much weight must be added?

The one link that interests me can be found here:

http://www.calculatoredge.com/new/torque.htm#torque