We been missing this all these years.

[Fletcher]

1. ... My feeling is; the wheels had continuous, constant torque. If I'm right about that; then, any periodic restoring or resetting of GPE is futile. Which also means the restoration of GPE has to be continuous, not intermittent.

One aspect of that is; the center of gravity is always to the down side of the wheel, to produce constant torque. Which seems to be what Bessler is suggesting.

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2. The question is how to achieve that? There aren't very many ways that it can be done. A Roberval type or style of balance gives a sense of it but, if there is a way to adapt it, I don't know how.

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3. Another way is with the so called Ring & Rollers, (that no one likes), however they do give constant torque, to the wheel. If a way could be found to displace them (continuously).

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4. Right. MT-15 and the prime mover. For him to know and us to find out. I guess it has to mean two movers or, two sets of weights.

Hi Sam ..

1. B. does seem to be suggesting that the CoM / CoG stays to one side of the axle - he says paraphrased 'as long as the weights stay out of the CoG and can't find their PQ' .. to have any torque the down-going weights have to lose more GPE than is gained on the up-going side .. B's. one-way wheels had to be tied down in any position, indicating a positive torque in any position which seems to confirm the preposition ..

2. the Roberval does give a visual "sense of it" i.e. displaced CoG - but as discussed the naked Roberval does not lose ( or gain ) any GPE, therefore there is no torque, altho visually it can be easily seen that the CoM / CoG is displaced to one side of the axle ..

A. There are ways to adapt a Roberval, and make it into a torque unbalanced wheel format - add weights to one side as per the water wheel analogy with mass entering from high up and exiting from low down - the "shot" needs to be lifted again to complete the circuit but we can get torque and rotation - temporarily un-pin one of the 2 vertically aligned pivots that make the parallelogram into a Roberval - it will have torque, and rotate, and lose GPE - but needs a restoration force ..

B. The subject of this thread - one-way bearings / sprag clutches allow biased movement in one direction only, possibly aiding the constant displacement quandary of the system Com / CoG and appearing somewhat like the Roberval visuals show ..

3. Your ring and rollers - they do make a torque if they are physically displaced to one side - that currently requires a force to be applied - you're working on it ..

4. MT15 - the second of 2 CCW illustrations in MT - there clearly are 2 'weights, or movers' as you/we speculate - he shows us clearly imbalancing weights sets i.e. the system CoM / CoG is well and truly to the lhs of the main axle - but it also just as clearly needs their PE to be restored / lifted i.e. a lifting force has to be applied, that does not penalize the wheel .. he also says that the prime mover can not be seen or deduced, a by association and mention in this illustration it is the missing piece of the puzzle that does the restoration / lifting imo ..
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I'll write something further on this in the next day or two in my own topic when I can get a clear run at it ..

[Sam Peppiatt]

Fletcher,
Maybe you can figure it out. It's got me stumped-------------------Sam

[agor95]

That's the big problem with rotating weights. The center of mass of the wheel always has to stay to the down side of it.

I'm finding it difficult to describe accurately. Maybe you can do better.

I generally think along the lines that a device needs to keep it's centre of mass to the left of a Counter Clockwise rotation.
In the convention of these things that is a positive torque.

The centre of mass moves around wanting to be below the axle. But does not achieve this and is moved away from the centre line.

Regards

[johannesbender]

@general , the way its written does not indicate to me that it is the cog of a wheel .

It sounds like tge cog of the earth , because the cog of a wheel with displaced weights of equal number of weights where some are farther one side and some closer the other side will always be towards the farther displaced weights .

And the cog of a wheel where there are more weight to one side than another will always be towards the more weight .

The cog will follow the weight , so it cannot be logical to say when he writes the weight must remain out of the cog that it means the cog must remain to one side .

The logical conclusion is that he means a weight will always fall and apply its force as long as it stays out of the cog of the earth .

He talks about two things here , the point of rest and the cog .

That is why he also includes by saying as long as they do not reach their point of rest or state of equalibrium .