Bellows

[preoccupied]

14 diameter outerwheel. 5 diameter inner wheel. Outer wheel has an advantaged gear ratio of 1.5*2=6 because a swing from the top right weight on the outerwheel to the bottom left weight on the outer wheel turns the inner wheel 22.5 degrees. 0 degrees 6*14=84, 45 degrees 6*10=30, 90 degrees 6*0=0 or momentum only, and on the far left it's momentum minus 60... 5+2+2+3+3+4+4=25 is the total weights on the inner wheel....

In this idea I've made my lever longer and my high gear ratio higher by suggesting that I can accept part of the swing of driving being excess momentum or I MEAN that the inner wheel will have to gain force from the swinging of the outer wheels weights and not just the outer wheels pull on gravity. Like, the outer wheel turns at a high advantage and then is expected to keep swiming with enough force to go an extra 45 degrees. The weights only apply force at right angle to the angles there because that's the only position where the gravity is pulling on it with positive force, and after it leaves the right angle, it must push on the wheel using its remainder swinging forces. I think my brain is on vacation so take what you can get out of this.

I do not know how to calculate momentum build up of a weight at a certain speed. This would be something I would need a link to? If anybody does a good tutorial. The idea requires that the weight fall on the outer wheel with enough force that its remainder force can swing another 45 degrees on its own and push the inner wheel.

Now, the lever would be even longer if it could swing higher hypothetically. And likewise the gear ratio would be even higher advantage then. It just seems like by trying to move beyond the leverage and go straight into the leverage that can be used from the excess forces in a swinging weight that maybe super great advantage leverage will build up enough to wow my brain really is on vacation it will build up leverage by requiring more swing. The wheel would have to be pushed into motion before it would start running at its leverage advantage if the weights aren't in the correct position due to where the outer wheel would balance if it were not in motion.

If I only had a brain.

[preoccupied]

What I've got here in ms painting "harpta derpta" is 3.5:1 gear ratio so that when the weight on the outer wheel turns 157.5 the inner wheel will move the smaller inner wheel 45 degrees. This gives the outer wheels single weigth a leverage of 35 and the inner wheels leverrage should always be about 4 with all of its weights.

The outer wheel will always drive the wheel and fall to the bottom if it wants to and stop there at the bottom. Though it has excess stroke on its lever if it completes the full swing. I am trying to see if the excess stoke from the full swing can lift a group of driven weights because of the seemingly greater increase in mechanical advantage than normal lever arrangements. What I notice is, is that the inner wheel gets smaller, so the outer wheels lever is therefore larger by comparison and simultaneously the gear ratio is higher allowing even more leverage on all accounts the further I hypothetically place the destination of the full stroke of the larger wheel.

[preoccupied]

1.875*10=18.75 leverage for the weight on the falling wheel becauese 168.75 stroke is driving a 90 degree stroke on the smaller inner wheel. If it's any indication of how much force would be left over on the falling side of the larger wheel 16.78/18.75=89.333% of its fall is preserved for the remainder of the swing on the left. If we let the wheel say it's perfect and that the weight would fall as high as it drops then the wheel will want to lift to about one square under the horizon. The hypothetical destination for the weight on the outer wheel is 2 squares under the horizon. The next variable is how much resistance the weight is taking from the weight on the inner wheel when the outer wheel climing on the left with excess swing. It looks like it will start with about 1.3 leverage on the inner wheels weight when the outer wheel passes its fall and starts to rise but that amount gets smaller as the outer wheels remaining force reduces.

I think this follows Bessler's Clues!. When Bessler said weights applied force at 90 degrees to the axis. I believe he meant that there was positive pull of gravity for 90 degrees along the rim of the wheel. Then when he says weights gained force from their own swinging I think he meant that gravity no longer applied force to the driving part of the wheel but rather the remaining excess force of the swinging does. That would suggest by this interpretation of those two clues that this is Bessler's Wheel!!!

[johannesbender]

I am not sure I follow what is doing what in connection with what here , not to be rude or
sound sarcastic , I am not sure what the drawings represent in motion .