IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?

[PeterAX]

To ovyyus.
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WHERE IS THE WRONG PHYSICS?!
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Asking my simple question for the 1st time: Do you have any objections against any of items 1 - 16 below? Yes or no? (If yes, then specify exactly which item you do not agree with and why.)
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1) Look again at PART 3 of the link https://www.youtube.com/watch?v=xX14NK8GrDY&t=24s . Focus on the “upper� zigzag case.
2) Ma = 1 kg.
3) Mb = 4 kg.
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4) Va’ = pre-zig-zag velocity of the blue component = 1 m/s = const.; Va’ = V1.
5) Vb’ = pre-zig-zag velocity of the black component = 0 m/s; the black component is motionless.
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6) Va� = during-zig-zag velocity of the blue component = variable and comparatively difficult (but not impossible) to calculate.
7) Vb� = during-zig-zag velocity of the black component = variable and comparatively difficult (but not impossible) to calculate.
8/ Vy = during-zig-zag velocity of each couple blue rod-blue ball along the Y-axis = variable and comparatively difficult (but not impossible) to calculate.
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9) Va�’ = post-zig-zag velocity of the blue component = 0.6 m/s = const.; Va�’ = V2.
10) Vb�’ = post-zig-zag velocity of the black component = 0.1 m/s = const.; Vb�’ = V3.
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11) According to the third Newton’s law and to the related law of conservation of linear momentum we can write down the equalities
((Ma) x (Va’)) + ((Mb) x (Vb’)) = ((Ma) x (Va�’)) + ((Mb) x (Vb�’)) <=>
<=> ((Ma) x (Va’)) + 0 = ((Ma) x (Va�’)) + ((Mb) x (Vb�’)) <=>
<=> (Ma) x (Va’) = ((Ma) x (Va�’)) + ((Mb) x (Vb�’)) <=>
<=> (1 kg) x (1 m/s) = ((1 kg) x (0.6 m/s)) + ((4 kg) x (0.1 m/s)) <=>
<=> 1 kg.m/s = 1 kg.m/s.
12) In one word, the values of Va�, Vb� and Vy are actually of no interest to us. Actually only the values of Va’, Va�’ and Vb�’ are of interest to us as these three values determine the validity of the third Newton’s law and the related law of conservation of linear momentum.
13) The mass of each couple blue rod-blue ball is much smaller than the mass of the blue T-shaped component. For example if Ma=1kg, then the mass of each couple blue rod-blue ball must be equal to, let’s say, 0.0001 kg (and even smaller).
14) In our numerous real experiments we strongly reduce friction and the mean experimental values of Va�’ and Vb�’ are equal to 0.5999992 m/s and to 0.0999997 m/s, respectively, that is, Va�’ = 0.5999992 m/s and Vb�’ = 0.0999997 m/s. The latter clearly shows that the experimental error (due to friction) is much smaller than 1 % and this experimental error is perfectly acceptable.
15) Let me remind only again (it is written in the explanatory text of the link https://www.youtube.com/watch?v=xX14NK8GrDY ) that the zigzags generate a mechanical effect (let us call this mechanical effect the "X effect"), (a) which is absolutely identical and equivalent to friction and (b) which does not generate heat. (We take gravity and friction out of equation and consideration.) And really even if the mean experimental value of force of friction inside the zigzag channels is equal to 0.0000001 N (our last experimental result), then the "X effect" still remains and can be clearly observed as in PART 3 of the link above.
16) And now we can easily calculate the pre-zig-zag and post-zig-zag kinetic energies of the bodies, taking part in the experiment. That is, we can write down the inequalities
(0.5) x (Ma) x (Va’) x (Va’) > ((0.5) x (Ma) x (Va�’) x (Va�’)) + ((0.5) x (Mb) x (Vb�’) x (Vb�’)) <=>
<=> (0.5) x (1 kg) x (1 m/s) x (1 m/s) > ((0.5) x (1 kg) x (0.6 m/s)x (0.6 m/s)) + ((0.5) x (4 kg) x (0.1 m/s) x (0.1 m/s)) <=> 0.5 J > 0.2 J
The last three inequalities unambiguously show a severe violation of the law of conservation of mechanical energy in this particular case.
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============================
WHERE IS THE WRONG PHYSICS?!
============================
Do you have any objections against any of the above items 1 - 16? Yes or no? (If yes, then specify exactly which item you do not agree with and why.)
Looking forward to your answer for the 1st time. (Only one word -- either "yes" or "no"!)

[ovyyus]

WHERE IS THE WRONG PHYSICS?!

Your animation shows two side by side systems with components falling under the influence of gravity. Why are the falling components not accelerating as they fall?

[PeterAX]

To ovyyus.
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Stop imitating pathological lack of understanding thus trying to manipulate the audience in a clumsy and unskillful manner! The animation illustrates SOLELY AND ONLY THE BASIC PRINCIPLE OF OPERATION of the zigzag method and nothing else! And I am deeply surprised that two weeks ago you admitted the validity of the zigzag concept and now all of sudden you totally change your mind and start asking stupid questions! I think that we are playing a fair game! Or may be I am wrong?

[ovyyus]

You admit your "animation/simulation" shows wrong physics. How can you win a Nobel Prize showing wrong physics!?

[PeterAX]

To ovyyus.
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You declare that the zigzag concept is a wrong physics and therefore you declare and pretend to be a highly qualified expert in physics. Therefore you could easily solve the simple physics problem below and could easily answer the two simple questions below.
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Consider carefully and thoroughly again (and many times, if necessary) the link https://www.youtube.com/watch?v=xX14NK8GrDY
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Ma = 1 kg
Mb = 4 kg
V1 = 1m/s = const
Ffr. = force of friction inside the zigzag channels = 0.0000001 N. (The latter can be further decreased as many times as you want.)
N = number of zigzags = 10. (The value of N can be either increase or decreased as many times as you want.)
Shapes of the zigzags = sinusoids. (The latter can replaced by any other curve patterns.)
V2 = ? (How many meters per second is V2 equal to?)
V3 = ? (How many meters per second is V3 equal to?)
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Simply answer the above two simple questions.
Looking forward to your two answers.

[ovyyus]

I'm not your trained monkey. Please don't blame me for pointing out your "animation/simulation" shows wrong physics.

[PeterAX]

To ovyyus.
=================
The answering of the two questions V2 = ? and V3 = ? is of key importance for the zigzag concept. But you keep constantly avoiding to answer these two simple questions. You are not honest and you do not play a fair game.
But let us check again your honesty. Please answer the two simple questions below, if possible.
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V2 = ? (How many meters per second is V2 equal to?)
V3 = ? (How many meters per second is V3 equal to?)
------------------------------
Simply answer the above two simple questions, if possible.
Looking forward to your two answers.

[ovyyus]

Lazy researchers don't win Nobel prizes. Please do your own work and report back when you can demonstrate something that works.

[PeterAX]

To ovyyus.
===================
I am already absolutely sure that you are not an expert in mechanics. On the contrary, I am already absolutely sure that you are simply an amateur. Because otherwise you would notice immediately that the invalidity of the law of conservation of mechanical energy and/or the invalidity the law of conservation of linear momentum in the zigzag device does/do not depend on the values of V2 and V3. Do you understand what I am talking about? I am sure you don't.

[Sam Peppiatt]

Dear PeterAX,

I think your zig-zag would be very difficult to build. Could it be one vertical zig-zag, instead of two side by side? That would make it a lot easer to build.

Also perhaps only two changes in direction, instead of seven, would it still demonstrate the same thing?

I'm afraid there would be big problems at the point(s), where the slope changes direction-------------Sam

[Tarsier79]

Sam. GeorgeBasic cannot build anything. He is a poorly constructed computer program.

[Sam Peppiatt]

Tarsier79,

I've tried to imagine how it might be done. But, can't think of a good way to build it. One thing is for sure. I couldn't do it----------------Sam

[PeterAX]

To those stubborn amateurs here in this forum, who simply reject obvious physical reality.
===================================================
Consider carefully and thoroughly again (and many times, if necessary!) the link https://www.youtube.com/watch?v=xX14NK8GrDY
-------------------------------------------
Ma = 1 kg
Mb = 4 kg
V1 = 1m/s = const
Ffr. = force of friction inside the zigzag channels = 0.0000001 N. (The latter can be further decreased as many times as you want.)
N = number of zigzags = 10. (The value of N can be either increased or decreased as many times as you want.)
Shapes of the zigzags = sinusoids. (The latter can replaced by any other curve patterns.)
V2 = ? (How many meters per second is V2 equal to?)
V3 = ? (How many meters per second is V3 equal to?)
------------------------------------------
Simply answer the above two simple questions.
Looking forward to your two answers for the 2nd time.

[Sam Peppiatt]

PeterAX,

Please forgive me, I don't have a clue. My level of understanding is very low.
I'm not good at math and am ignorant of metrics.

I've never under stood your zig- zag.


For a reactionless drive; it has to push off from some thing, which I don't think it does, right?

How can it be a perpetual motion machine, if it doesn't turn any thing?

What can I say, except I really don't understand it-------------------------Sam

[PeterAX]

To Sam Peppiatt.
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Hi Sam,
1) Well, I feel like I need to apologize to you PERSONALLY for being a little more rude than necessary. But this WaltzCee/Tarsier79/MrTim "gansters" family:) makes me some time a little nervous!:)
2) About the zigzags. Why don't you make a simple zigzag wire construction and carry out some simple experiments on your kitchen table? (I remember that some of our first zigzag experiments many years ago were just of that kind.) Not pressing, only suggesting.
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It's always a pleasure for me to correspond with you.
Regards,