IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?

[WaltzCee]

To Sam Peppiat.
=================
Hi Sam,
Thank you for your post.
-------------------------------
I would suggest a somewhat "crazy" idea.:)
What would happen if we use two identical gravity wheels, (a) which are fixed to a common axis and (b) which work in opposite phase? That is, when the first gravity wheel's pendulum potential energy/centrifugal force is at its maximum the second gravity wheel's potential energy/centrigugal force is at its minimum. In other words, what would happen if we try to build a two-phase mechanical equivalent of a two-phase electric motor? Or to use three identical gravity wheels thus trying to build a three-phase mechanical equivalent of a three-phase electric motor? What do you think? Would this system work?
Looking forward to your answer.
Regards,

This "crazy" idea demonstrates a slight ignorance of physics. Specifically

What would happen if we use two identical gravity wheels, (a) which are fixed to a common axis and

Topologically the wheels would be one. Any point on wheel One (Pa) would have
the same point on wheel Two (Pb).

The most egregious example of ignorance is

That is, when the first gravity wheel's pendulum potential energy/centrifugal force is at its maximum

[Sam Peppiatt]

Peter AX,

You give me far too much credit, I'm hardly an expert. It's like the more I learn the less I know. Your basic idea is correct; you could have n number of wheels on the same shaft as far as I know, and as many pends. on a wheel as practical.

I think you are still asking if the "phase" of the two wheels could be different.

No, I don't think so. A gravity wheel does have some limitations. The best operating point to swing a pendulum in, for CW rotation, is at 9:00, and at 3:00 for CCW rotation. because these two points are 90 degrees, to the force of gravity, with the best leverage. to turn the wheel. I'm afraid we are stuck with a more or less single phase operation; if I understand your question correctly.

It's been difficult to get a gravity wheel to do anything! Right now I'm trying to do it, the simples way possible. I'm sure in the future others, including your self, could see better ways to do it. It's capabilities are limited only by your imagination-----------------------Sam

[WaltzCee]

To Tarsier79/MrTim?WaltzCee.
======================
Take your medicine and stop discussing things, which you are absolutely not familiar with.

Your hypocracy is showing, mame.

[PeterAX]

To Sam Peppiat.
----------------------------------
Hi Sam,
Hi dear colleague,
Thank you for your reply.
1) Your modesty impressed me too much! I'll be glad to be your partner (and more precisely, to be your assistant:)) in the further development of your gravity wheel basic concept.
2) Need some time to consider carefully and thoroughly your last post and understand in depth the essence of your last explanations. Please give me some time, if possible. I will write to you in the nearest future.
3) Please keep me constantly informed what happens. Always ready to help.
Regards,
Peter

[PeterAX]

Asking my two simple questions for the 18th time.
--------------------------------------------
1) Consider carefully and thoroughly (and many times!) the link https://www.youtube.com/watch?v=xX14NK8GrDY .
--------------------------------------------
2) Assume that:
a) Ma = 1 kg;
b) Mb = 4 kg; the value of Mb can be either increased or decreased as many times as you want;
c) V1 = 1m/s = const;
d) Ffr. = force of friction inside the zigzag channels = 0.0000001 N; the latter can be further decreased as many times as you want;
e) N = number of zigzags = 10; the value of N can be either increased or decreased as many times as you want;
f) Shapes of the zigzags = sinusoids; the latter can be replaced by any other curve patterns.
--------------------------------------------
3) It is evident that if V2 = 0.6 m/s and if V3 = 0.1 m/s, then (a) the law of conservation of linear momentum is valid and (b) the law of conservation of mechanical energy is invalid.
--------------------------------------------
4) It is evident that if V2 = 0.8 m/s and if V3 = 0.3 m/s, then (a) the law of conservation of linear momentum is invalid and (b) the law of conservation of mechanical energy is valid.
--------------------------------------------
5) It is evident that both (a) the law of conservation of linear momentum and (b) the law of conservation of mechanical energy are actually invalid simultaneously in this special particular zigzag case.
--------------------------------------------
So let us ask again our two simple questions for the 18th time.
--------------------------------------------
QUESTION 1: V2 = ? (How many meters per second is V2 equal to?)
QUESTION 2: V3 = ? (How many meters per second is V3 equal to?)
--------------------------------------------
Looking forward to your two answers for the 18th time.

[Sam Peppiatt]

Hi Peter AX,

Let me back way up. A pendulum by it's self won't do spit! It has to have, what Calloway refers to a one way bearing, on the pin that it pivot's on. If you have such a pend. with it's bearing, it will turn a wheel. Like so:

Given, a wheel 3 feet in diameter, with one pend. 10 inches long, weight 1 1/2 lbs. , at a radius of 16 inches, and counter balanced on the opposite side, so that the wheel is normally balanced.

If you lift / rotate the pendulum up 90 degrees so that it is horizontal pointing into the center; (at this point it is temporarily locked to the wheel by the one way bearing), then let go of it, the wheel will make three almost four complete revolutions, (CCW).

(continued I have to let my spell checker cool off)

[Sam Peppiatt]

Peter AX,

Fallow up. Where was I; as soon as the wheel turns 90 degrees, to the 12:00 position, the bearing automatically releases. The importance of all of this is the wheel goes from being OOB by a full pound, to perfectly balanced in a fraction of a second.

The problem becomes; how to flip the pendulums. I found by simply stretching a spring from the the pend. to a point near the center of the wheel, and rotating the wheel by hand CCW, it, the spring, will automatically swing the pend, into the center at the 3:00 position every time it comes around.

However, the spring also wants to swing them in on the down side as well, and other places to cause havoc. This is the way it stands at the moment. Some how I / we have to find a way to keep all of the pendulums from screwing, (please forgive my French), every thing up, from about 12:00 all the way around back to 3:00--------------------------------------Sam

PS Thanks for caring about my ideas!!

[PeterAX]

Hi Sam,
Hi dear colleague,
Thank you for your last two posts.
It's a pleasure for me to be your partner (and more precisely, your assistant:)).
1) Well, as far as I can see it's a matter of a somewhat quite sophisticated purely mechanical automated system, that is, something like a purely mechanical control program. The latter leads me to the next "crazy" idea: couldn't we use some simple computer program, controlling the, more or less, sophisticated sequence of steps that perform the gravity wheel system components? (This is only a suggestion.)
2) Please give me some time to consider carefully and thoroughly your last two posts. I will write to you in the nearest future.
3) Meanwhile if you make some progress in your R&D work, then please write to me. I'll be glad to discuss the new theoretical/experimental results of yours.
Regards,
Peter

[PeterAX]

Asking my two simple questions for the 19th time.
--------------------------------------------
1) Consider carefully and thoroughly (and many times!) the link https://www.youtube.com/watch?v=xX14NK8GrDY .
--------------------------------------------
2) Assume that:
a) Ma = 1 kg;
b) Mb = 4 kg; the value of Mb can be either increased or decreased as many times as you want;
c) V1 = 1m/s = const;
d) Ffr. = force of friction inside the zigzag channels = 0.0000001 N; the latter can be further decreased as many times as you want;
e) N = number of zigzags = 10; the value of N can be either increased or decreased as many times as you want;
f) Shapes of the zigzags = sinusoids; the latter can be replaced by any other curve patterns.
--------------------------------------------
3) It is evident that if V2 = 0.6 m/s and if V3 = 0.1 m/s, then (a) the law of conservation of linear momentum is valid and (b) the law of conservation of mechanical energy is invalid.
--------------------------------------------
4) It is evident that if V2 = 0.8 m/s and if V3 = 0.3 m/s, then (a) the law of conservation of linear momentum is invalid and (b) the law of conservation of mechanical energy is valid.
--------------------------------------------
5) It is evident that both (a) the law of conservation of linear momentum and (b) the law of conservation of mechanical energy are actually invalid simultaneously in this special particular zigzag case.
--------------------------------------------
So let us ask again our two simple questions for the 19th time.
--------------------------------------------
QUESTION 1: V2 = ? (How many meters per second is V2 equal to?)
QUESTION 2: V3 = ? (How many meters per second is V3 equal to?)
--------------------------------------------
Looking forward to your two answers for the 19th time.

[PeterAX]

Let us push forward together the technology progress!
---------------------------------------------
Let us popularize in any possible way the link https://www.youtube.com/watch?v=xX14NK8GrDY as it contains an absolutely free new technology information, which is able to make better the life of any human being on Earth.
=========================
1) Having in mind the link https://www.youtube.com/watch?v=xX14NK8GrDY assume that:
a) Ma = 1 kg;
b) Mb = 4 kg; the value of Mb can be either increased or decreased as many times as you want;
c) V1 = 1m/s = const;
d) Ffr. = force of friction inside the zigzag channels = 0.0000001 N; the latter can be further decreased as many times as you want;
e) N = number of zigzags = 10; the value of N can be either increased or decreased as many times as you want;
f) Shapes of the zigzags = sinusoids; the latter can be replaced by any other curve patterns.
--------------------------------------------
2) It is evident that if V2 = 0.6 m/s and if V3 = 0.1 m/s, then (a) the law of conservation of linear momentum is valid and (b) the law of conservation of mechanical energy is invalid.
--------------------------------------------
3) It is evident that if V2 = 0.8 m/s and if V3 = 0.3 m/s, then (a) the law of conservation of linear momentum is invalid and (b) the law of conservation of mechanical energy is valid.
--------------------------------------------
4) It is evident that (a) the law of conservation of linear momentum and (b) the law of conservation of mechanical energy are invalid simultaneously in this special particular zigzag case, which is described in the link https://www.youtube.com/watch?v=xX14NK8GrDY .
========================
Let us popularize in any possible way the link https://www.youtube.com/watch?v=xX14NK8GrDY as it contains an absolutely free new technology information, which is able to make better the life of any human being on Earth.
--------------------------------------------
Let us push forward together the technology progress!

[Sam Peppiatt]

To Peter AX,

Yes, a computer program would be good but impossible for me to do------------------------------Sam

[PeterAX]

To Sam Peppiat.
====================
Hi Sam,
Hi dear colleague,
Thank you for your reply.
------------------------------------
1) Ok, we'll focus then on the purely mechanical program/computer version, which is even as if a much better approach. Much easier for a practical realization/repairing/adjustment.
2) I have started doing some calculations, related to the suitable timing and sequence of steps, that have to be performed by the, more or less, numerous mechanical components of the system. Need some time. I'll write to you in the nearest future.
3) Meanwhile if you obtain some new theoretical/experimental results, then please inform me immediately, if possible. I'll be glad to discuss with you these new results.
Regards,
Peter

[PeterAX]

Asking our two simple questions for the 20th time.
--------------------------------------------
1) Consider carefully and thoroughly (and many times!) the link https://www.youtube.com/watch?v=xX14NK8GrDY .
--------------------------------------------
2) Assume that:
a) Ma = 1 kg;
b) Mb = 4 kg; the value of Mb can be either increased or decreased as many times as you want;
c) V1 = 1m/s = const;
d) Ffr. = force of friction inside the zigzag channels = 0.0000001 N; the latter can be further decreased as many times as you want;
e) N = number of zigzags = 10; the value of N can be either increased or decreased as many times as you want;
f) Shapes of the zigzags = sinusoids; the latter can be replaced by any other curve patterns.
--------------------------------------------
3) It is evident that if V2 = 0.6 m/s and if V3 = 0.1 m/s, then (a) the law of conservation of linear momentum is valid and (b) the law of conservation of mechanical energy is invalid.
--------------------------------------------
4) It is evident that if V2 = 0.8 m/s and if V3 = 0.3 m/s, then (a) the law of conservation of linear momentum is invalid and (b) the law of conservation of mechanical energy is valid.
--------------------------------------------
5) It is evident that both (a) the law of conservation of linear momentum and (b) the law of conservation of mechanical energy are actually invalid simultaneously in this special particular zigzag case.
--------------------------------------------
So let us ask again our two simple questions for the 20th time.
--------------------------------------------
QUESTION 1: V2 = ? (How many meters per second is V2 equal to?)
QUESTION 2: V3 = ? (How many meters per second is V3 equal to?)
--------------------------------------------
Looking forward to your two answers for the 20th time.

[PeterAX]

Let us push forward together the technology progress!
---------------------------------------------
Let us popularize in any possible way the link https://www.youtube.com/watch?v=xX14NK8GrDY as it contains an absolutely free new technology information, which is able to make better the life of any human being on Earth.
=========================
1) Having in mind the link https://www.youtube.com/watch?v=xX14NK8GrDY assume that:
a) Ma = 1 kg;
b) Mb = 4 kg; the value of Mb can be either increased or decreased as many times as you want;
c) V1 = 1m/s = const;
d) Ffr. = force of friction inside the zigzag channels = 0.0000001 N; the latter can be further decreased as many times as you want;
e) N = number of zigzags = 10; the value of N can be either increased or decreased as many times as you want;
f) Shapes of the zigzags = sinusoids; the latter can be replaced by any other curve patterns.
--------------------------------------------
2) It is evident that if V2 = 0.6 m/s and if V3 = 0.1 m/s, then (a) the law of conservation of linear momentum is valid and (b) the law of conservation of mechanical energy is invalid.
--------------------------------------------
3) It is evident that if V2 = 0.8 m/s and if V3 = 0.3 m/s, then (a) the law of conservation of linear momentum is invalid and (b) the law of conservation of mechanical energy is valid.
--------------------------------------------
4) It is evident that (a) the law of conservation of linear momentum and (b) the law of conservation of mechanical energy are invalid simultaneously in this special particular zigzag case, which is described in the link https://www.youtube.com/watch?v=xX14NK8GrDY .
========================
Let us popularize in any possible way the link https://www.youtube.com/watch?v=xX14NK8GrDY as it contains an absolutely free new technology information, which is able to make better the life of any human being on Earth.
--------------------------------------------
Let us push forward together the technology progress!

[Sam Peppiatt]

Hi Peter AX,

Can you do simulations / sims? If, I could get the wheel to work, a sim of it would be invaluable. My road to a working wheel reminds me of your ZigZag. A giant ZigZag! But tapered, with the zigs slowly becoming shorter and shorter-----------------------------------Sam