Terror Bloat

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Oxygon
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Terror Bloat

Post by Oxygon »

http://cryptome.org/terror-bloat.htm

the last sentence I find most truthful...
"A man with a new idea is a crank until he succeeds."~ M. Twain.
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ken_behrendt
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re: Terror Bloat

Post by ken_behrendt »

Tierney wrote:
"Why," he asks, "have they not been sniping at people in shopping centers, collapsing tunnels, poisoning the food supply, cutting electrical lines, derailing trains, blowing up oil pipelines, causing massive traffic jams, or exploiting the countless other vulnerabilities that, according to security experts, could so easily be exploited?"
Part of the answer is that the US's security system IS working and cells are being disrupted before they achieve critical mass and can do some 9/11 style mayhem.

However, most of these cells are probably amateur freelancer types and, even if they did manage to get through the multi layers of security, would only kill a few dozen people at most.

However, the really big terrorist extravaganzas will be far better planned and will use all that Al Qaeda has "learned" in recent years. These types of attacks will definitely be intended to be on the scale of 9/11 and could take thousands of lives.

Right now, the northern and southern borders of the US are very "porous" and virtually anybody could walk across them with a suitcase nuke or vials of anthrax spores to cause a serious terrorist incident. Soon, I hope, with the use of electronic barriers, this vulnerability will be ended.

Generally, I do not agree with the author that the terrorist risk has been exaggerated. If someone was to ask the government of the US on 9/10 if we were vulnerable to a terrorist attack on a major city that would have cost thousands of lives, the suggestion would have provoked laughter and a pat denial of the possibility.

The price of freedom is eternal vigilence...


ken
On 7/6/06, I found, in any overbalanced gravity wheel with rotation rate, ω, axle to CG distance d, and CG dip angle φ, the average vertical velocity of its drive weights is downward and given by:

Vaver = -2(√2)πdωcosφ
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