Hello,
I am not very good in mechanical calculation and I would like to know what kind of power (in Watts) we could expect from a Bessler wheel.
Let's take the wheel of Gera as example. It was around 2m in diameter. Let's suppose that it had 8 wheights of 2 Kg each and that the average gravity center was 10 cm on a side of the axe.
I do understand that this wheel would have an average torque of:
2x 8 x 9,81 x 0,1 = 15,7 Nm
But after that, how can I calculate the power that a such wheel could deliver??
Thanks to help me...
Genmurphy.
Mechanical power calculation (help needed)
Moderator: scott
re: Mechanical power calculation (help needed)
I am also in need for a help
There are two rods with weights, connected together with a gear and the left side is fixed to a wheel. The wheel is turning right-wise. When the right side is in 0°, it strikes another rod, which is outside the wheel, and it is steady, not turning or moving. Now, while the wheel is turning, it is supposed both weights (the left weight together with the right weight) will be lifted. When the wheel turns 1°, the left is rising 1°+1°=2° because of the right rod, while the right weight rises only 1° (hence the need of a gear to connect these rods together). After a turn of 15° of the wheel, the left weight is in the position of 180° and the right weight in the position of 15° relatively to the wheel, or in new coordinates, where we put the wheel again at 0°, the left weight is in 165° and the right weight in 0°. I hope the situation is clear enough.
The question is now, how do I calculate the Power F needed to lift the weights? Both F1 and F2 are equal, and the length of the rods are 1m, the same as the radius of the wheel. The Wheel is turning with a torque of 1,7*F1. Is this torque of the wheel enough to lift the weights?
There are two rods with weights, connected together with a gear and the left side is fixed to a wheel. The wheel is turning right-wise. When the right side is in 0°, it strikes another rod, which is outside the wheel, and it is steady, not turning or moving. Now, while the wheel is turning, it is supposed both weights (the left weight together with the right weight) will be lifted. When the wheel turns 1°, the left is rising 1°+1°=2° because of the right rod, while the right weight rises only 1° (hence the need of a gear to connect these rods together). After a turn of 15° of the wheel, the left weight is in the position of 180° and the right weight in the position of 15° relatively to the wheel, or in new coordinates, where we put the wheel again at 0°, the left weight is in 165° and the right weight in 0°. I hope the situation is clear enough.
The question is now, how do I calculate the Power F needed to lift the weights? Both F1 and F2 are equal, and the length of the rods are 1m, the same as the radius of the wheel. The Wheel is turning with a torque of 1,7*F1. Is this torque of the wheel enough to lift the weights?
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re: Mechanical power calculation (help needed)
I'm sorry, I couldn't understand what you are describing. Perhaps you can download a demo version of Working Model 2, and simulate it.
Disclaimer: I reserve the right not to know what I'm talking about and not to mention this possibility in my posts. This disclaimer also applies to sentences I claim are quotes from anybody, including me.
re: Mechanical power calculation (help needed)
Working Model is somewhat cheating. I made many models with my idea, and all worked fine. But then, theory says, it should not. I have only a demo version of WM2D, so I can't save it and post here. Calculations with excel shows also that it will work. Surely, I am missing something. Before I venture to a real construction, I will check all possibilities, where an unseen flaw could hide.