M Turbine Question & Answers

[agor95]

Anyone thinking of creating a test rig.

1. Two double pendulums opposite each other with ratchet connecting joins. This allows counter clockwise rotation.

2. Main hub rotation is clockwise up to operational speed.

3. Most important no weights in the first attempt.

If you are just reading then fine; it is safer.

The next stage in the concept development is simulations.

[agor95]

The graphs show a weight's CF, in yellow, increasing as the radius does the same. With a 26rpm, CF is greater than acceleration due to gravity at 1.32m (4.33ft). The gravity line is in red.

So the design of a M. Turbine will have 5ft hub spokes with 1ft MT51 Item A components.

The test of a 20rpm does not reach the CF greater than gravity pull.

To have a device working at 20rpm would require the fire method explained in a previous post.

This would increase rotation of the weight. That would assist in placing the weight into a greater radius.

[agor95]

The motion of the bounce back is the most complex.

The tangential velocity of weight at 6 feet radius on a 26rpm hub frame.

How would item A move and would it resolve to be in the position shown?

Do we need to loss some K.E. in this interaction?

If we lose some K.E. then that is why a heavy internal pendulum is present.

This allows the weight to bounce of the rubber hammer part of the pendulum; something like as seen in MT13.

Possibly requires two that alternate in their roll of impacter.

[ME]

You could set the Cr to 0.9, see: https://en.wikipedia.org/wiki/Inelastic ... on#Formula

[agor95]

The blue ball is the same mass and size as the yellow ball.
The yellow ball is a little closer.

If you download the V. Python example you can see that for yourself.

1. The blue ball's gravitational force's
effective torque is reduced by the force's angle.
In the above it is only compressional.
2. Both weights start with zero vertical movement.

3. The graph shows the blue ball is accelerated
more than the yellow in the first phase.
Then close to being zero; constant speed almost.

4. The yellow ball has a constant acceleration.

Has anyone either by physical proto-type or sim
proved the maximum rotation speed.?

[james.lindgard]

@agor95,
Research has shown me that acceleration of an over balanced wheel can be accurately calculated.

[Fcdriver]

Extending the spoke from 2 to 4 o'clock which retracts the spoke from 8 to 10 o'clock. Without the hammer or ball is closer to causing rotation. If The hammer device is not the prime mover, but causing the weighted spoke to extend and retract you might get rotation, if you can control the timing, by off setting the harmonic motion. You will find that lifting the hammer extended can move more weight, on the extending spoke, while it is at a 45 degree angle. Extending the secondary spoke opposite your hammer, more than offsets any weight gained, by extending the hammer weight. The hammer has to be lighter than the spoke which shifts back and forth, not heavier, a weighted spoke would be the prime mover. But with all of the movement you are still staying balanced, and not gaining advantage.

[agor95]

@james.lindgard

Thanks James I will keep on the path.

[agor95]

@Fcdriver

Thanks your idea has merit.

Time for another demo. V. Python version.

? 6 people want me to stop 4 want me to continue ?