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Both the 'stator' and rotor have an MoI of 1 kg-m²-rad/s. They share the same axis, and are alternately interconnected by a motor and clutch.
Whatever its speed as it departs 12 o' clock TDC, the motor applies just enough torque to prevent the 'stator' from accelerating under gravity... instead, accelerating the rotor.
At 6 o' clock BDC the motor switches off and the clutch engages, locking both parts together. Since their MoI's are equal, these inellastic collisions halve the per-cycle velocity rise and so burning half the input energy. The system then coasts the 'stator' back up to TDC whereupon the clutch disengages and the cycle repeats.
Hence we have a fairly-ordinary motor, in which all of the counter-momentum is being sunk to gravity.
The motor is controlled for 'acceleration', and a quick'n'dirty feedback loop is applied by metering the green 'stator' weight's acceleration, and feeding it back into the motor's 'acceleration' field, multiplied by the "Inverse Acceleration Multiplier" of "-3". Note the RPM's in the top-left corner - you see the weight's speed is kept more or less constant thru each descent, while the wheel is accelerated by the corresponding counter-torque.
Inevitably, the efficiency tracks ½mV². The reason for this is simply the natural decrease in the "time spent gravitating" each cycle as RPM's increase, and thus the shorter each cycle period gets.
On the one hand, the system is successfully "dragging itself around by its own bootstraps" - no torque is applied to the outside world at the axis, for example (though counter-torques are being earthed via gravity) - it's a mutually self-accelerating system, a rise in momentum in an otherwise closed-system of masses interacting about a common axis.. so seems to come very close to bearing all the hallmarks of an angular N3 violation...
..except it cannot gain energy. So, not a meaningfully 'effective' N3 violation, by the only metric we care about.
Like i say, what's going wrong is the ever-decreasing per-cycle momentum yields. The amount of angular inertia is not changing, hence the amount of work / load applied to the motor is not rising with velocity.. However there's simply less time per cycle for that work to produce momentum, as speed rises.
Thus perhaps the only value in the above simple failure is to highlight and underline this fundamental constraint..
So the burning question becomes, "how do you produce constant momentum per cycle, in spite of rising RPM's?".. because if you can do that, in precisely the same manner as the above sequence of "reactionless accelerations & subsequent inelastic collisions", then the efficiency does not track ½mV²; on the contrary, if we can maintain constant per-cycle input energy and constant per-cycle momentum yield, then we create a divergent inertial frame, and efficiency rises with velocity..
..for instance, the minimum energy that can be paid for 1 kg-m/s or 1 kg-m²-rad/s is half a Joule (0.5 J), so if we can maintain that for say, five cycles, then we'd pay 5 * 0.5 J = 2.5 J total input energy; for a pair of 1 kg inertias now moving at 2.5 m/s, they'd have a KE of 6.25 J, hence we'd have an efficiency of 260%.
If you chew over these points carefully, i believe you too will come to the conclusion they're inherently irreconcilable - we cannot attain mechanical OU if the momentum gain principle is sychronised to external coordinate space!
..it has to be asynchronous to the wheel angle / rotation!
Thus a full 'cycle', from the perspective of the momentum-gain mechanism, is however many degrees it takes to impart that constant momentum, despite rising RPM's!
In short, our 'window of opportunity' for 'doing stuff' inside the wheel - the 'period' of our mechanisms - need not, and probably should not, be inextricably tied to any external aspects of 'angle' such as vertical / horizontal orientation or even limited to 360° - at least, not if it's sourcing our momentum, anyway.
This was my last 'Eureka!' moment, Sunday bath-time.. s'got me all excited again. Finally, the breakthrough i'd been looking for.. The 'stumbling block' is the false constraint of the artifice of Cartesian coordinate space, and our natural N3-based perspective of what constitutes a "cycle"... but in a divergent FoR, such predispositions must go out the window.. a truly 'effective' angular N3 violation means that in the successful system, a "360° cycle" is using more angular displacement than this in our static, external FoR! And considerably moreso, the faster it gets..
So Bessler probably couldn't've been 'milking' momentum from gravity, as i'd been investigating - that's probably an inherently-impractical pursuit, since the gravity vector is static, and can't accelerate around with the system..
I think the breakthrough experiments could be very simple:
W/ gravity off:
• consider a rotor, with two smaller rotors mounted on either side, in balance
• these two smaller ones have equal MoI's
• one of them is a 'variable MoI' - its mass can be pulled into its axial center. It may be comprised of two opposing radially-sliding masses, also mounted on bearings to remain free to rotate about their own axes.
• apply equal torque to each smaller rotor, spinning each in opposite directions, thus cancelling each other's counter-torques, and imparting no 'orbital' counter-momentum back to the central axis.
• now pull the vMoI masses into their axial center, effectively destroying their share of angular momentum. This action's reactionless, applying no torque back to the central rotor. This results in the vMoI spinning fast, but with negligable MoI, or thus, momentum.
• brake both smaller rotors back to stationary; the vMoI has negligable momentum, so the central rotor and thus whole system is spun up by decelerating the momentum imparted to the other, unmodified small rotor. Thus if each were initially given 1 kg-m²-rad/s, the net system momentum has risen by this much
• we've paid for motor torque * angle. This metric is speed-invariant - the energy cost's the same, regardless of the initial speed of the central rotor.
Spinning up the smaller rotors in opposite directions will always cost the same workload, regardless of how high the 'orbital' rotation speed gets. They always begin stationary relative to the central rotor, and are spun up to the same relative speed each cycle. Thus input torque * angle is constant.
• we've also done work against CF force, destroying half our momentum. Since axial CF is more or less invariant of orbital CF, this cost, too, is more or less constant. It'll start out low, because the vMoI will be the 'counter-rotating' rotor (we're destroying counter-momentum), however as RPM's pick up, it'll initially be counter-rotating relative to the external frame, hence say if orbital speed is 1 rad/s and each smaller rotor's spun up to 1 rad/s in opposing directions, then one of them's at a real speed of 2 rad/s whilst the other's no longer rotating at all, hence its axial CF force is nil.. type stuff..
Point is, that if we can simply keep piling on 1 kg-m²-rad/s each 'cycle' (regardless of how many degrees of rotation that may encompass), and our input energy isn't squaring up with velocity... this should inevitably result in OU.
So even if the energy cost's 1 J of T*a plus 50 J more work done against CF force, that's still a constant input energy of 51 J per cycle... and at some point, past some critical orbital velocity, another 1 kg-m²-rad/s of angular momentum's gonna cause a greater rise in rotational KE than the 51 J it costs to produce..
..this is what i'll be testing next in simulation.