Force required to lift an object-a possible effect?


[ Follow Ups ] [ Post Followup ] [ Bessler Discussion Board ] [ FAQ ] [ Back to BesslerWheel.com ]

Posted by Vector Viper (205.162.15.2) on April 13, 2003 at 18:14:37:

Think of a safe weighing 1000 lbs...if you lift it straight
up, you lift all of this. If the safe is rolled up a ramp,
you 'hold' less weight, the ground 'holding' the rest-at the
expense of a further linear distance traveled, right?
(You push less than 1000 lbs to lift the weight)
Now think of a 45 degree incline. I would expect 1/2 the force
held by you, the ground holding the rest. BUT, looking at the
geometry, (think a square with a 45 angle cut into it) you
do NOT travel 2 times as far!
1:is this correct?
2:Is there real energy savings here?
2:can this be be exploited in some way?

Or am I just blowing smoke here?

I do think that if you push/pull at 90 degrees to gravity
up the 45 degree incline, you do a lot MORE work, since
you are driving the weight into the incline itself...

Hmmmm...I bring this up because of I new design I am working on
using 'sliding weights' outside of a wheel.

Viper "Hello, anyone here?"



Follow Ups:



Post a Followup

Name:
E-Mail:
Subject:
Comments:
(Archived Message)


[ Follow Ups ] [ Post Followup ] [ Bessler Discussion Board ] [ FAQ ] [ Back to BesslerWheel.com ]