Re: Correction - sorry..

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Posted by Nick Hall (195.74.122.243) on May 08, 2003 at 14:25:49:

In Reply to: Correction - sorry.. posted by Øystein Rustad on May 08, 2003 at 12:50:24:

Øystein wrote:

: : %OU for a gravitywheel would be Input related to output where
: : Input = negative work, and output is positive work acting as torque * distance acting on the axle or rim..
: : OU = Wdown (negative work) / Wup (positive work) * 100 - 100

Now that makes more sense...and implies that total available power is related to physical size (Which is, of course, expected).

That will help to set the bells ringing....!

Thanks

Nick

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Comments:	: Øystein wrote: : : : %OU for a gravitywheel would be Input related to output where : : : Input = negative work, and output is positive work acting as torque * distance acting on the axle or rim.. : : : OU = Wdown (negative work) / Wup (positive work) * 100 - 100 : Now that makes more sense...and implies that total available power is related to physical size (Which is, of course, expected). : That will help to set the bells ringing....! : Thanks : Nick
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