e=mc^2
Moderator: scott
In SI definition.
The SI definition makes certain assumptions about the laws of physics. For example, it is assumed that the particle of light, the photon, is massless. If the photon had a small rest mass, the SI definition of the metre would become meaningless because the speed of light would change as a function of its wavelength
The SI definition makes certain assumptions about the laws of physics. For example, it is assumed that the particle of light, the photon, is massless. If the photon had a small rest mass, the SI definition of the metre would become meaningless because the speed of light would change as a function of its wavelength
A video search for
cambell gravity wheel
http://uk.youtube.com/watch?v=67n40cD7AFw&NR=1
Shows pythagorean triangles.
cambell gravity wheel
http://uk.youtube.com/watch?v=67n40cD7AFw&NR=1
Shows pythagorean triangles.
re: e=mc^2
Ant,
What it will be for you is 'not to fade into oblivion", rather consider my input as a challenge. An incentive to debate and substantiate that I am wrong. Consider it the catalyst for innovation on your part.
To suggest fading into oblivion due to the statement from one individual does not paint much of an image upon yourself. Suggest you read the above "PM" quote with a little more indulgence.
I ask you, what is the connection between a lot of mathematical Pythagoras talk, Einstein theory and scissor mechanisms? And what is so magical about them?
You appear to be a person of some intellect, possibly with an above average IQ, also a person with an obsession for numbers and squares.
Can you in layman's terms please describe this relationship with a gravity powered mechanism.
Your craftsmanship in building your scissors of extended links is to be applauded. It is quite obvious that they open and close by there own weight in the vertical direction of their position. But to force them open against gravity is another story. Also they weigh the same open or closed.
Ralph
What it will be for you is 'not to fade into oblivion", rather consider my input as a challenge. An incentive to debate and substantiate that I am wrong. Consider it the catalyst for innovation on your part.
To suggest fading into oblivion due to the statement from one individual does not paint much of an image upon yourself. Suggest you read the above "PM" quote with a little more indulgence.
I ask you, what is the connection between a lot of mathematical Pythagoras talk, Einstein theory and scissor mechanisms? And what is so magical about them?
You appear to be a person of some intellect, possibly with an above average IQ, also a person with an obsession for numbers and squares.
Can you in layman's terms please describe this relationship with a gravity powered mechanism.
Your craftsmanship in building your scissors of extended links is to be applauded. It is quite obvious that they open and close by there own weight in the vertical direction of their position. But to force them open against gravity is another story. Also they weigh the same open or closed.
Ralph
re: e=mc^2
Ant .. imo you have shown that you are as driven as many of the rest of us & good for you.
A lack of discussion or response usually means that not everybody has studied your ideas in detail so don't want to make seemingly uneducated comments, alternatively they have a familiar 'gut' feeling that the over-balanced wheel, no matter how it is 'organised' to work, is a dead end & so cannot get excited about any variation of this theory, no matter how clever or persuasive the argument might be. You could call this being close minded while others might see it as the voice of experience talking to them. Either way it hasn't stopped you building your design which is the ultimate test of a theory - if it works you & many of us will be ecstatic that a solution to gravity wheels has been found at long last - if it doesn't work you & others won't give up but will attempt to isolate the reason it didn't work this time. As you've probably gathered by now many of this community are very good at analysing faults in a design but so far non are experts at what is required to get an over-balance wheel to work & we are all on the same learning curve along with you in that regard.
I for one watch with interest your endeavors & admire your tenacity & the fact that you are constructing to move from theory to reality.
A lack of discussion or response usually means that not everybody has studied your ideas in detail so don't want to make seemingly uneducated comments, alternatively they have a familiar 'gut' feeling that the over-balanced wheel, no matter how it is 'organised' to work, is a dead end & so cannot get excited about any variation of this theory, no matter how clever or persuasive the argument might be. You could call this being close minded while others might see it as the voice of experience talking to them. Either way it hasn't stopped you building your design which is the ultimate test of a theory - if it works you & many of us will be ecstatic that a solution to gravity wheels has been found at long last - if it doesn't work you & others won't give up but will attempt to isolate the reason it didn't work this time. As you've probably gathered by now many of this community are very good at analysing faults in a design but so far non are experts at what is required to get an over-balance wheel to work & we are all on the same learning curve along with you in that regard.
I for one watch with interest your endeavors & admire your tenacity & the fact that you are constructing to move from theory to reality.
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re: e=mc^2
Fletcher; I really appreciate you and your theories,. however, a balanced wheel with a prime mover WILL work very nicely. jlk
re: e=mc^2
I think I agree wholeheartedly James ?! We might be getting into semantics again about whether a wheel is called balanced or over-balanced, as I read your statement - for my money I call a wheel with a CoG shifted away from the axle in general terms unbalanced, regardless of its stationary position [like a grindstone at rest] - if it is CoG shifted to one side of the axle it becomes over-balanced - if it rotates & finds it keel position, where the CoG is directly below the axle, it is technically balanced & at rest, again in the x coordinate but not the y coordinate - additionally when the CoG is at the Center of Rotation & coincides with the wheel axle [like a flywheel] then this is completely balanced [in both x & y coordinates]- but these are minor differences of the vernacular kind.
I simple terms, that we all inherently understand, an over-balanced wheel will have self sustaining rotational ability providing you have a source of energy or force [the Prime Mover] to cause the wheel weights to shift & lift to full potential energy each cycle that also keeps the wheels CoG to one side of the axle, maintaining the constant over-balance condition.
If I have misunderstood what you mean by 'balanced wheel' in the context you used it, then please enlighten me ?
I simple terms, that we all inherently understand, an over-balanced wheel will have self sustaining rotational ability providing you have a source of energy or force [the Prime Mover] to cause the wheel weights to shift & lift to full potential energy each cycle that also keeps the wheels CoG to one side of the axle, maintaining the constant over-balance condition.
If I have misunderstood what you mean by 'balanced wheel' in the context you used it, then please enlighten me ?
Re: re: e=mc^2
The magic about the constant in a magic square is that the value is the same in all directions. In an odd magic square the numbers can be arranged from magic to what I label as a linear sequence. The movement patterns in all odd magic squares can show a scissor action movement.rlortie wrote:Ant,
I ask you, what is the connection between a lot of mathematical Pythagoras talk, Einstein theory and scissor mechanisms? And what is so magical about them?
The diagonal in a linear to magic square moves as a straight line clockwise.
1 2 3
4 5 6
7 8 9
8 1 6
3 5 7
4 9 2
1 2 3
4 5 6
7 8 9
8 1 6
3 5 7
4 9 2
The minimum Pythagorean Triangle has three sides.Can you in layman's terms please describe this relationship with a gravity powered mechanism.
One side measures 5 (1^2+b^2) and is called the hypotenuse. The other two sides are 3 and 4 and are set at a 90 degree angle.
In normal magic squares the three square would be numbered
8 1 6
3 5 7
4 9 2
If the start number is changed the energy value is no longer 15. Here is a constant of 30.
Beginning number= 06 End number= 14 mean(average or whole number in each cell)=10
13 06 11
08 10 12
09 14 07
the magic 4^2 can also have a constant of 30
First number= 00 Last number 15. No whole number mean.
00 14 13 03
11 05 06 08
07 09 10 04
12 03 02 15
the magic 5^2 can also have a constant of 30
a=-6 z=18. Mean(average)=6
10 17 -6 01 08
16 -2 00 07 09
-3 -1 06 13 15
03 05 12 14 -4
04 11 18 -5 02
thanks!!!Your craftsmanship in building your scissors of extended links is to be applauded. It is quite obvious that they open and close by there own weight in the vertical direction of their position. But to force them open against gravity is another story. Also they weigh the same open or closed.
Ralph
re: e=mc^2
Ralph .. they may weigh the same whether open of closed but their CoM's are different & since they are attached by at least one pivot they will have different leverage characteristics when either open of closed because the CoM has changed accordingly. N.B. This is sometimes overlooked when studying vertical operating scissors e.g. a weight will compress a vertical scissor but the CoM of the scissor itself will drop to a lower height along with the weight attached to its end. Conversely, when a weight falls & extends a vertical [upsidedown] scissor the CoM of the scissor also lowers. Not sure if this has any relevance to Ant's mech's & how they are deployed ?
As far as I can see Ant's scissors extend once they are below horizontal, much like water always finds the lowest position available - but as you say getting them to close uphill is a struggle & yet it appears insufficient torque would be generated to 'swing' the mech far enough to allow it to close downhill again on the opposite side of the wheel - I may have misunderstood how Ant's mechs are supposed to operate however ?
As far as I can see Ant's scissors extend once they are below horizontal, much like water always finds the lowest position available - but as you say getting them to close uphill is a struggle & yet it appears insufficient torque would be generated to 'swing' the mech far enough to allow it to close downhill again on the opposite side of the wheel - I may have misunderstood how Ant's mechs are supposed to operate however ?
The weight of 8 oscillates a little, clockwise the 3 layered pecker opens out on the right and folds in on the left, forced by the 3 @ 30 square waves.
The square should be incremented by 1/5 of what ever unit you want to use, that scale gives it a spring in its step.
The one I am now working on has 1/10 increments.
The square should be incremented by 1/5 of what ever unit you want to use, that scale gives it a spring in its step.
The one I am now working on has 1/10 increments.
re: e=mc^2
Searl has much to answer for :D
He does not have the shapes I discovered - Cwantum Cubes. I read three of his books, One I got translated into readable English, 50 were printed, I even have the authorization from him on a stamp sealed bit of paper. I played with excel on and off for a number of years before I realised and believed the 6 arm version. Growing needs, a book shop in Glastonbury used to stock his books as well as a few photos of my square waves.Searl has much to answer for
I distributed 40 photos on Glastonbury Tor ages ago around 1999, each with 5p stuck to them. I only experienced half a dent during that time once, right in the head - had a head ache for days, I had to have aspirin in my dressing gown, I have since realised the significance.
My square wave even made an appearance with my explanation to two people at the David Blaine man in a box stunt at Tower Bridge, London.
I have a photo of the event somewhere, can't see much the print is a bit too dark...
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It looks like I will need to reverse the spine or double the spine. One spine on the 'top side' makes the angle wrong to close swiftly when retracting, I have not played with elastic yet. On Tuesday I will have the time to strip and re-do to see if the spine works better located at the 'bottom side' or both.
These little adjustments are so time consuming...
I have upgraded all weights now to MDF 7 thick Pythagorean Triangles as bars are 7 thick etc...
three arms each have 14 weights.
Mathmatically I put forward the suggestion a triangle composed of 3 dots.
Magnify each dot - it is a sphere I can see it as a square...
2
2 2
To turn this into a 2 square it becomes
0 1
2 3
So 0=-1 as in 0 1 2 3 rather than 1 2 3 4 or 1 1 1 1.
So -1=-4.
This is binary placing
0.00 as in 0 of 4
0.01 as in 1 of 4
0.10 as in 2 of 4
0.11 as in 3 of 4
1.00 as in 1 of 2 and 0 of 4
Anyways because binary 0 is none of 2 for 'mass' each square must have 2 inside.
2 2
2 2
If you now start a count, with this view you can always start the count at 2, because no matter what square you pick there is always 2 in it.
So...
2 3
4 5
There are two pairs of 7's
2 3 . 2 3
4 5 . 4 5
So 14 Pythagorean Triangles for each square wave in sets of 2 representing a magnified dot sounds reasonable to me.
U?
Ant
These little adjustments are so time consuming...
I have upgraded all weights now to MDF 7 thick Pythagorean Triangles as bars are 7 thick etc...
three arms each have 14 weights.
Mathmatically I put forward the suggestion a triangle composed of 3 dots.
Magnify each dot - it is a sphere I can see it as a square...
2
2 2
To turn this into a 2 square it becomes
0 1
2 3
So 0=-1 as in 0 1 2 3 rather than 1 2 3 4 or 1 1 1 1.
So -1=-4.
This is binary placing
0.00 as in 0 of 4
0.01 as in 1 of 4
0.10 as in 2 of 4
0.11 as in 3 of 4
1.00 as in 1 of 2 and 0 of 4
Anyways because binary 0 is none of 2 for 'mass' each square must have 2 inside.
2 2
2 2
If you now start a count, with this view you can always start the count at 2, because no matter what square you pick there is always 2 in it.
So...
2 3
4 5
There are two pairs of 7's
2 3 . 2 3
4 5 . 4 5
So 14 Pythagorean Triangles for each square wave in sets of 2 representing a magnified dot sounds reasonable to me.
U?
Ant
re: e=mc^2
In pictures as an example is what I intend to do...
The grey stopps and spine change position to give the blue effect.
The weights are drawn on the other side but it gives the idea.
The grey stopps and spine change position to give the blue effect.
The weights are drawn on the other side but it gives the idea.