Posted by Øystein rustad (213.145.185.102) on April 14, 2003 at 07:39:59:
In Reply to: Force required to lift an object-a possible effect? posted by Vector Viper on April 13, 2003 at 18:14:37:
Funny as it seems, the force you need to supply is not 0,5 but
0,707
To be more excact M * sin45 = 707 lbs
Now put that in, and you see that it matches the lenght 100%
So long...
Øystein
: Think of a safe weighing 1000 lbs...if you lift it straight
: up, you lift all of this. If the safe is rolled up a ramp,
: you 'hold' less weight, the ground 'holding' the rest-at the
: expense of a further linear distance traveled, right?
: (You push less than 1000 lbs to lift the weight)
: Now think of a 45 degree incline. I would expect 1/2 the force
: held by you, the ground holding the rest. BUT, looking at the
: geometry, (think a square with a 45 angle cut into it) you
: do NOT travel 2 times as far!
: 1:is this correct?
: 2:Is there real energy savings here?
: 2:can this be be exploited in some way?
: Or am I just blowing smoke here?
: I do think that if you push/pull at 90 degrees to gravity
: up the 45 degree incline, you do a lot MORE work, since
: you are driving the weight into the incline itself...
: Hmmmm...I bring this up because of I new design I am working on
: using 'sliding weights' outside of a wheel.
: Viper "Hello, anyone here?"