Re: Yet ANOTHER idea(I THINK this is a good one, though!:-D :-))

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Posted by ovyyus (203.26.14.3) on May 27, 2003 at 17:33:34:

In Reply to: Re: Yet ANOTHER idea(I THINK this is a good one, though!:-D :-)) posted by Joel L. Lewis on May 27, 2003 at 14:40:19:

Hi Joel,

A balance beam with equal weights at each end and a pivot at its centre will adjust itself according to the vertical position of the pivot relative to the COG of the beam.

If the pivot is above the COG of the beam (ie: the beam is bottom heavy), then the beam will always come to rest in a horizontal position.

If the pivot is below the COG of the beam (ie: the beam is top heavy), then the beam will always come to rest with one end down.

By lowering or raising the weights connected at the ends of the beam you can alter the relative position of the beam COG and the pivot. This effectively changes whether the beam is top heavy, bottom heavy or 'balanced' and the beam will behave accordingly. Hope this helps.

Regards, ovyyus

: I'll try to clarify.:-) Take that same lever, and hang one of the weight's from it's position. The lever remains level, because, as I recently discovered to my embarrassment, the weight's still counterballance. So the lever remains level, but now the weights THEMSELVES are deffinitely NOT level. The weight that's hanging from one end is obviously lower.

: Still with me? Easy enough so far, right?

: Okay, now imagine tilting the lever until the two weights themselves are level with each other. What happens then when the lever moves to regain equilibrium by leveling? Keeping in mind that the end with the weight hanging from it is pointing up, and the end with the weight attached is pointing down, the end of the lever with the weight directly attached will move UP, corret? And the end from which the other weight hangs will move down, correct? Therefore, the weight directly attached to the lever will move up, and the weight hanging from the other end will move down, the same distance-and therefore, in finding equilibrium and leveling itself, the lever has also moved the weight's APART, and what is there then but to allow the weights to dissengage the lever(or sides of a wheel, if you will), and directly engage a seperate wheel to level themselves and start the cycle again?

: Were you able to follow me that time, I hope?

: : So the lever is self-leveling.. now, If I could make different things happen just from drawing a line, I'd be set! Or some magic string.. Maybe I'm the one lost..
: :

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Comments:	: Hi Joel, : A balance beam with equal weights at each end and a pivot at its centre will adjust itself according to the vertical position of the pivot relative to the COG of the beam. : If the pivot is above the COG of the beam (ie: the beam is bottom heavy), then the beam will always come to rest in a horizontal position. : If the pivot is below the COG of the beam (ie: the beam is top heavy), then the beam will always come to rest with one end down. : By lowering or raising the weights connected at the ends of the beam you can alter the relative position of the beam COG and the pivot. This effectively changes whether the beam is top heavy, bottom heavy or 'balanced' and the beam will behave accordingly. Hope this helps. : Regards, ovyyus : : : I'll try to clarify.:-) Take that same lever, and hang one of the weight's from it's position. The lever remains level, because, as I recently discovered to my embarrassment, the weight's still counterballance. So the lever remains level, but now the weights THEMSELVES are deffinitely NOT level. The weight that's hanging from one end is obviously lower. : : Still with me? Easy enough so far, right? : : Okay, now imagine tilting the lever until the two weights themselves are level with each other. What happens then when the lever moves to regain equilibrium by leveling? Keeping in mind that the end with the weight hanging from it is pointing up, and the end with the weight attached is pointing down, the end of the lever with the weight directly attached will move UP, corret? And the end from which the other weight hangs will move down, correct? Therefore, the weight directly attached to the lever will move up, and the weight hanging from the other end will move down, the same distance-and therefore, in finding equilibrium and leveling itself, the lever has also moved the weight's APART, and what is there then but to allow the weights to dissengage the lever(or sides of a wheel, if you will), and directly engage a seperate wheel to level themselves and start the cycle again? : : Were you able to follow me that time, I hope? : : : So the lever is self-leveling.. now, If I could make different things happen just from drawing a line, I'd be set! Or some magic string.. Maybe I'm the one lost.. : : :
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