Posted by Øystein Rustad (148.122.151.83) on August 25, 2003 at 13:53:27:
In Reply to: 8 weights per revolution posted by Jeff on August 25, 2003 at 08:07:04:
Hello, I copy and paste my post about centrifugal / centripetal forces in the the Bessler / any wheel...
Lets see at what RPM the centrifugal forces will be equal to gravity ! (at the rim)
RPM(Fg = Fc) = (g * r)^1/2 * (60 / pi*2r)
g = 9,8
r = 1,825m
: Resault = 22,1 RPM ! (with diameter = 3,65 meters)
(The largest wheel) I know the force would be bigger in some of the smaller wheels, if the weights where placed the same distance from rim / hub though..
: At this RPM the weights are "weightless" at the top and
: have F = 2g at the bottom.
Good luck :-)
Øystein
: Second: Maybe Oystein has already posted about this, but could someone calculate (again the mathematics) the rpm needed for a 10 foot diameter wheel so a weight at the rim would not fall, but would remain at the rim?
: Jeff